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3 years ago

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A sealed vessel contains 0.200 mol of oxygen gas, 0.100 mol of nitrogen gas, and 0.200 mol of argon gas. The total pressure of t

he gas mixture is 5.00 atm. The partial pressure of the argon is_________.
(A) 0.200 atm
(B) 0.500 atm
(C) 1.00 atm
(D) 2.00 atm
(E) 5.00 atm

1 answer:

babunello [35]3 years ago

8 0

Answer:

D

Explanation:

We can use the mole ratio to calculate the partial pressure. The total number of moles is 0.2 + 0.2 + 0.1 = 0.5 moles

Now, we know that the mole fraction of the argon gas would be 0.2/0.5

The partial pressure is as follows. To calculate this, we simple multiply the number of moles by the total pressure.

0.2/0.5 * 5 = 1.0/0.5 = 2.00atm

D

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