This is an incomplete question, here is a complete question.
Consider the following equilibrium at 100°C.
![COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)](https://tex.z-dn.net/?f=COBr_2%28g%29%5Crightleftharpoons%20CO%28g%29%2BBr_2%28g%29)
Concentration at equilibrium:
![[COBr_2]=1.58\times 10^{-6}M](https://tex.z-dn.net/?f=%5BCOBr_2%5D%3D1.58%5Ctimes%2010%5E%7B-6%7DM)
![[Co]=2.78\times 10^{-3}M](https://tex.z-dn.net/?f=%5BCo%5D%3D2.78%5Ctimes%2010%5E%7B-3%7DM)
![[Br_2]=2.51\times 10^{-5}M](https://tex.z-dn.net/?f=%5BBr_2%5D%3D2.51%5Ctimes%2010%5E%7B-5%7DM)
If a system has a reaction quotient of 2.13 × 10⁻¹⁵ at 100°c, what will happen to the concentrations of COBr₂, Co and Br₂ as the reaction proceeds to equilibrium?
Answer : The concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.
Explanation :
Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.
The given balanced chemical reaction is,
![COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)](https://tex.z-dn.net/?f=COBr_2%28g%29%5Crightleftharpoons%20CO%28g%29%2BBr_2%28g%29)
The expression for reaction quotient will be :
![Q=\frac{[CO][Br_2]}{[COBr_2]}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5BCO%5D%5BBr_2%5D%7D%7B%5BCOBr_2%5D%7D)
In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.
Now put all the given values in this expression, we get
![Q=\frac{(2.78\times 10^{-3})\times (2.51\times 10^{-5})}{(1.58\times 10^{-6})}=4.42\times 10^{-2}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%282.78%5Ctimes%2010%5E%7B-3%7D%29%5Ctimes%20%282.51%5Ctimes%2010%5E%7B-5%7D%29%7D%7B%281.58%5Ctimes%2010%5E%7B-6%7D%29%7D%3D4.42%5Ctimes%2010%5E%7B-2%7D)
The given equilibrium constant value is,
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
There are 3 conditions:
When
that means product > reactant. So, the reaction is reactant favored.
When
that means reactant > product. So, the reaction is product favored.
When
that means product = reactant. So, the reaction is in equilibrium.
From the above we conclude that, the
that means product < reactant. So, the reaction is product favored that means reaction must shift to the product (right) to be in equilibrium.
Hence, the concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.