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4 years ago

Which statement is true regarding methane and ammonia?

2 answers:

6 0

The options for given question are as follow,

1) Methane molecules show hydrogen bonding.
2) Ammonia molecules show hydrogen bonding. 
3) Methane has stronger hydrogen bonding than ammonia. 
4) Both the compounds do not show hydrogen bonding. 
5) Both the compounds have strong hydrogen bonding.

Answer:
Correct answer is Option-2 (Ammonia molecules show hydrogen bonding).

Explanation:
Hydrogen bond interactions are formed when a partial positive hydrogen atom attached to most electronegative atom of one molecule interacts with the partial negative most electronegative element of another molecule. So, in Ammonia hydrogen gets partial positive charge as nitrogen is highly electronegative. While the C-H bond in Methane is non-polar and fails to form hydrogen bond interactions.

Olenka [21]4 years ago

4 0

The answer is B. Trust me!!!

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Is my answer correct

Cerrena [4.2K]

Yes it’s correct.
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3 years ago

How many Sr2+ ions are in a mole of Sr3(PO4)2 ?

jeka94

Each molecule of Sr₃(PO₄)₂ contains 3 moles of Sr
So 3 moles of Sr⁺² ions are in one mole of Sr₃(PO₄)₂.

7 0

3 years ago

Can torque rods desaturate reaction wheels

katrin [286]

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4 0

3 years ago

How many moles are in a 275g sample of K2CrO3

Marrrta [24]

Answer:

There are approximately 1.54 moles in a 275 g sample of $K_2CrO_3$ .

Explanation:

To find out number of moles, fistly we have to calculate molecular mass of $K_2CrO_3$ .

There are 2 atoms of Potassium 1 atom of Chromium and 3 atoms of oxygen in the given compound.

For molecular mass we have to add the value of mass of 2 atoms of Potassium with mass of 1 atom of Chromium and with mass of 3 atoms of oxygen.

Atomic mass of Potassium = 39

Atomic mass of Chromium = 52

Atomic mass of Oxygen = 16

Now,

Molecular mass of $K_2CrO_3$ = $2\times 39+52+3\times 16=78+52+48=178\ gm$

The molecular mass of a compound is the mass of compound in one mole.

To find out the number of moles, we have to divide given mass of compound by its molecular mass.

$Number\ of\ moles=\frac{given\ mass}{molecular\ mass}$

$Number\ of\ moles=\frac{275}{178}= 1.54$

Hence the number of moles in 275 gm of $K_2CrO_3$ is 1.54.

8 0

3 years ago

ure carbon tetrachloride, CCl4, freezes at-23.00 ⁰C and has a kf of 29.8⁰C/m. The latest lot has a freezing point of-23.43⁰C. Wh

lesya692 [45]

Answer:

a) grams of this impurity per kg of CCl4 = 3.416 g/kg of solvent.

b) mass purity % = 99.66%

Explanation:

Given, the freezing point of pure CCl₄ = - 23°C

Presence of impurities lowers the freezing point to - 23.43°C

The freezing point depression constant, Kբ = 29.8°C/m

The lowered freezing point is related to all the parameters through the relation

ΔT = i Kբ × m

where ΔT is the lowered freezing point, that is, the difference between freezing point of pure substance (T⁰) and freezing point of substance with impurities (T).

i = Van't Hoff factor which measures how much the impurities influence/affect colligative properties (such as freezing point depression) and for most non-electrolytes like this one, it is = 1

Kբ = The freezing point depression constant = 29.8°C/m

m = Molality = ?

T⁰ - T = i Kբ m

- 23 - (-23.43) = 1 × 29.8 × m

m = 0.43/29.8 = 0.0144 mol/kg

Them we're told to calculate impurity of the CCl₄

we convert the Molality to (gram of solute)/(kg of solvent) first

Solute = C₂Cl₆

Molar mass = 236.74 g/mol

So, (molality × molar mass) = (gram of solute)/(kg of solvent)

(gram of solute)/(kg of solvent) = 0.0144 × 236.74 = 3.416 (gram of solute)/(kg of solvent)

Mass purity % = (1000 g of pure substance)/(1000 g of pure substance + mass of impurity in 1000 g of pure substance)

1000 g of solvent contains 3.416 grams of impurities

Mass purity % =100% × 1000/(1003.416)

Mass purity % = 99.66 %

3 0

4 years ago