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3 years ago

Which compound becomes less soluble in water as the temperature of the solution is increased?(1) HCl (2) KCl (3) NaCl (4) NH4Cl

Chemistry

2 answers:

aleksandrvk [35]3 years ago

4 0

Answer: Option (1) is the correct answer.

Explanation:

Compounds in which atoms transfer electrons result in the formation of ionic bond. Whereas when atoms in a compound share electrons then they result in the formation of covalent compounds.

Also, it is known that like dissolves like. Hence, water being an ionic compound itself dissolves other ionic compounds.

Thus, out of the given options HCl is a covalent compound, therefore, HCl is the compound that becomes less soluble in water as the temperature of the solution is increased.

ratelena [41]3 years ago

3 0

HCI are less soluble in water as the temperature of the solution is increased.

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The initial movement of groundwater into the atmosphere to form clouds is due to what?

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This is the water cycle and the process is Evaporation.

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3 years ago

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5. What is the mole fraction of NaOH in an aqueous solution that contains 31.0 % NaOH by mass?

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Answer:

16.8%

Explanation:

31% NaOH molar mass 40 gm

69% H2O molar mass 18 gm

1000 gm would be

310 gm NaOH or 310/40 = 7.75 moles

690 gm of H2O or 690/18 = 38.333 moles

7.75 / (7.75 + 38.333) = .168 mole fraction

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2 years ago

Which equation represents a redox reaction?

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Answer:

D. $2NaBr + Cl_2\rightarrow 2NaCl + Br_2$

Explanation:

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In this case, for the given set of chemical reactions, it is possible to infer that D. is a categorized as redox due to the following:

Since both chlorine and bromine remain as diatomic gases, their oxidation states in such a form is 0, but as anions with lithium cations they have a charge of - according to the following reaction and half-reactions:

$2NaBr + Cl_2\rightarrow 2NaCl + Br_2$

$Cl_2^0+2e^-\rightarrow 2Cl ^-\\\\2Br^- \rightarrow Br_2^0+2e^-$

Unlike the other reactions whereas no change in the oxidation states is evidenced.

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3 years ago

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why is a molecule of CO2 non polar even though the bonds between the carbon atom and the oxygen atoms are polar

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2 years ago

The standard free energy of formation, ΔG∘f, of a substance is the free energy change for the formation of one mole of the subst

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Answer:

B. 2 Na(s) + O₂(g) → Na₂O₂(s); ΔG∘f=−451.0 kJ/mol

D. 2 SO(g) + O₂(g) → 2 SO₂(g); ΔG°f=−600.4 kJ/mol

Explanation:

The spontaneity of a reaction is given by the value of the standard Gibbs free energy of the reaction (ΔG°rxn). The more negative is the ΔG°rxn, the more spontaneous is a reaction.

The ΔG°rxn can be calculated using the following expression:

ΔG°rxn = ∑np × ΔG°f(products) − ∑nr × ΔG°f(reactants)

By definition, the standard Gibbs free energy of formation of simple substances in their most stable state is zero. That is why, in the reaction of formation of a compound ΔG°rxn = ΔG°f(product).

Based on the standard free energies of formation, which of the following reactions represent a feasible way to synthesize the product?

A. N₂(g) + H₂(g) → N₂H₄(g); ΔG°f=159.3 kJ/mol.

Not feasible. ΔG°rxn = ΔG°f(product) > 0.

B. 2 Na(s) + O₂(g) → Na₂O₂(s); ΔG°f=−451.0 kJ/mol

Feasible. ΔG°rxn = ΔG°f(product) < 0.

C. 2 C(s) + 2 H₂(g) → C₂H₄(g); ΔG°f=68.20 kJ/mol

Not feasible. ΔG°rxn = ΔG°f(product) > 0.

D. 2 SO(g) + O₂(g) → 2 SO₂(g); ΔG°f=−600.4 kJ/mol

Feasible. ΔG°rxn = ΔG°f(product) < 0.

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3 years ago