All categories

3 years ago

Which compound becomes less soluble in water as the temperature of the solution is increased?(1) HCl (2) KCl (3) NaCl (4) NH4Cl

Chemistry

2 answers:

aleksandrvk [35]3 years ago

4 0

Answer: Option (1) is the correct answer.

Explanation:

Compounds in which atoms transfer electrons result in the formation of ionic bond. Whereas when atoms in a compound share electrons then they result in the formation of covalent compounds.

Also, it is known that like dissolves like. Hence, water being an ionic compound itself dissolves other ionic compounds.

Thus, out of the given options HCl is a covalent compound, therefore, HCl is the compound that becomes less soluble in water as the temperature of the solution is increased.

ratelena [41]3 years ago

3 0

HCI are less soluble in water as the temperature of the solution is increased.

You might be interested in

Dribbling a basketball harder into the floor makes it bounce higher is an example of what newton's law?

vodomira [7]

Newton’s third law, because a person(a) is acting upon the ball(b) by dribbling the ball on the floor

8 0

2 years ago

Name the following compounds:

ankoles [38]

A) cesium chloride
B) barium oxide
C) potassium sulfide
D) beryllium chloride
E) hydrogen bromide
F) aluminum fluoride

3 0

2 years ago

A particular reaction has an enthalpy and entropy of reaction of ∆H = +33 kJ/mol and ∆S = +0.15 kJ/mol⋅K. At the three indicated

Thepotemich [5.8K]

Answer:

Explanation: check my paage

4 0

2 years ago

A galvanic (voltaic) cell consists of an electrode composed of nickel in a 1.0 M nickel(II) ion solution and another electrode c

Andre45 [30]

Answer: The standard potential of the cell is 0.77 V

Explanation:

We know that:

$E^o_{Ni^{2+}/Ni}=-0.25V\\E^o_{Cu^{+}/Cu}=0.52V$

The substance having highest positive $E^o$ reduction potential will always get reduced and will undergo reduction reaction.

The half reaction follows:

Oxidation half reaction: $Ni(s)\rightarrow Ni^{2+}(aq)+2e^-$

Reduction half reaction: $Cu^{+}(aq)+e^-\rightarrow Cu(s)$ ( × 2)

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Putting values in above equation follows:

$E^o_{cell}=0.52-(-0.25)=0.77V$

Hence, the standard potential of the cell is 0.77 V

5 0

2 years ago

Derek lives in a hot, humid climate. He has two rose bushes in pots in his yard. The rose bushes grow quickly and bloom with lar

nikitadnepr [17]

the answer is A. Does temperature affect the growth of rose bushes because remember their asking u what question can you answer doing the investigation.

8 0

2 years ago