Answer:
6.2moles of Na are needed.
Explanation:
First, we need to generate a balanced equation for the reaction between sodium and chlorine to produce sodium chloride. This is illustrated below:
2Na + Cl2 —> 2NaCl
From the equation,
2moles of Na produced 2moles of NaCl.
Therefore Xmol of Na will produce 6.2moles of NaCl i.e
Xmol of NaCl = (2 x 6.2)/2 = 6.2moles
Therefore, 6.2moles of Na are needed to produce 6.2moles of NaCl
The volume of water vapour would be produced at 19°C and 780 torr is 548.5mL.
If 400 ml of CO2 is produced at 30°C at 740 torr, then number of moles can be calculated as:
By using ideal gas equation:
P1V1 = N1R1T1
P1 = pressure = 740torr
V1 = 400 ml = volume of CO2
R = Gas constant = 8.314
T = 273+30 = 303 k
740×400 = N1×8.314×303
N1 = (740×400) /(8.314×303) =117.5.
Chemical equation
C2H6 ---- 2CO2 + 3H2O.
As we noticed from the equation that
2 moles of CO2 = 3 moles of H2O
1 moles of CO2 × 1 moles of H2O
Then N2 = 117.5 moles of CO2 = 3/2 × 117.5 moles of H2O
By using ideal gas equation:
P2V2 = N2RT2
V2 = 3/2 × 117.5 × 8.314 × 292/ 780
= 548.5ml.
Thus, we found that the volume of water vapour would be produced at 19°C and 780 torr is 548.5mL.
learn more about ideal gas equation:
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Explanation:
The given reaction will be as follows.
So, equilibrium constant for this equation will be as follows.
![K_{c} = \frac{[CH_{3}OH]}{[CO][H_{2}]^{2}}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5Cfrac%7B%5BCH_%7B3%7DOH%5D%7D%7B%5BCO%5D%5BH_%7B2%7D%5D%5E%7B2%7D%7D)
As it is given that concentration of all the species is 2.4. Therefore, calculate the value of equilibrium constant as follows.
= 
= 0.173
Thus, we can conclude that equilibrium constant for the given reaction is 0.173.
Answer:
The gas was N₂
Explanation:
V = 3.6L
P = 2.0 atm
T = 24.0°C = 297K
R = 0.0821 L.atm/K.mol
m = 8.3g
M = molar mass = ?
Using ideal gas equation;
PV = nRT
n = no. Of moles = mass / molar mass
n = m/M
PV = m/M * RT
M = mRT / PV
M = (8.3*0.0821*297) / (2.0*3.6)
M = 28.10
Since X is a diatomic molecule
M = 28.10 / 2 = 14.05 g/mol
M = Nitrogen
X = N₂
The molar mass of Sb2S3 is approximately equal to 339.7 g/mol. We calculate the number of moles of Sb2S3 by dividing the given mass by the molar mass.
n = 23.5 g / (339.7 g/mol)
n = 0.0692 mols
To calculate for the number of formula units, we multiply the number of mols by the Avogadro's number,
number of formula units = (0.0692 mols)(6.022 x 10^3)
= 4.167 x 10^22 formula units
