Differentiate both sides wrt 
:
By the chain rule, we get
Solve for 
:
Answer: ]1, 2[
Step-by-step explanation:
![A \cap B=[0; 2[\\\\(A \cap B)-C=]1, 2[](https://tex.z-dn.net/?f=A%20%5Ccap%20B%3D%5B0%3B%202%5B%5C%5C%5C%5C%28A%20%5Ccap%20B%29-C%3D%5D1%2C%202%5B)
Answer:
2np + p²
Step-by-step explanation:
The general formula for the area of a square is A = s², where s = the length of one side of the square. In the case of the smaller square the area would be: n x n = n². Since the side of the larger square is 'p' inches longer, the length of one side is 'n + p'. To find the area of the larger square, we have to take the length x length or (n +p)².
Using FOIL (forward, outside, inside, last):
(n + p)(n+p) = n² + 2np + p²
Since the area of the first triangle is n², we can subtract this amount from the area of the larger square to find out how many square inches greater the larger square area is.
n² + 2np + p² - n² = 2np + p²
Answer:
I believe it would be answer 2)
Step-by-step explanation:
The team has 4 players and the line graph starts at 5 increasing to 9
