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Serga [27]
3 years ago
12

What is the verbal expression for 15+r

Mathematics
2 answers:
AysviL [449]3 years ago
7 0

Answer:

15 is added to r is the answer.

Step-by-step explanation:

Here we can see that one is a number and another is a variable which is named as 'r' here.

When we add a number ( which is called constant ) to a variable

then we write same as we speak

like 15 +r is verbally written as 15 is added to r .

exis [7]3 years ago
5 0
Your answer is going to be fifteen plus r
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Step-by-step explanation:

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4 0
3 years ago
PLZ HELP ASAP SOLVE SIMMILAR TRIANGLES LAST ONE
zvonat [6]
For this case by similarity of triangles we can use the following relationship:
 (x) / (9) = (5) / (15)
 We clear the value of x:
 x = ((5) / (15)) * (9)
 Rewriting:
 x = (1/3) * (9)
 x = 3
 Answer:
 
The value of x for this case is:
 
x = 3
3 0
3 years ago
Question 134 (plz help) (ps I luv u)
stiv31 [10]

Answer:

<B = 108 degrees

Step-by-step explanation:

<A = <B  <u><em> (Alternate Angles are congruent)</em></u>

So,

6x+18 = x+93

=> 6x-x = 93-18

=> 5x = 75

<em>Dividing both sides by 5</em>

=> x = 15

Now,

<B = x+93

=> <B = 15+93

=> <B = 108 degrees

6 0
3 years ago
A circular patio has a diameter of 35 yards. What is the circumference of the patio?
wolverine [178]
C=2πr=2·π·17.5≈109.95574
6 0
3 years ago
An aptitude test has a mean score of 80 and a standard deviation of 5. The population of scores is normally distributed. What pr
konstantin123 [22]

Answer:

2.28% of tests has scores over 90.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80, \sigma = 5

What proportion of tests has scores over 90?

This proportion is 1 subtracted by the pvalue of Z when X = 90. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 80}{5}

Z = 2

Z = 2 has a pvalue of 0.9772.

So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.

8 0
3 years ago
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