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3 years ago

What is the mirror formula for curved mirrors

Physics

2 answers:

julia-pushkina [17]3 years ago

7 0

Answer:

the answer is c of all the choices

Explanation:

Reika [66]3 years ago

3 0

The mirror formula for curved mirrors is:
$\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i}$
where
f is the focal length of the mirror
$d_o$ is the distance of the object from the mirror
$d_i$ is the distance of the image from the mirror

The sign convention that should be used in order to find the correct values is the following:
- $f$ : positive if the mirror is concave, negative if the mirror is convex
- $d_i$ : positive if the image is real (located on the same side of the object), negative if it is virtual (located on the opposite side of the mirror)

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A bowling ball with a momentum of 18kg-m/s strikes a stationary bowling pin. After the collision, the ball has a momentum of 13k

Veronika [31]

Answer:

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$P_2$ = Momentum of the ball after hit

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$\theta$ = Angle the pin makes with the horizotal after getting hit by the ball

Momentum in the x direction

$P_i=P_1\cos55^{\circ}+P_2\cos\theta\\\Rightarrow P_2\cos\theta=P_i-P_1\cos55^{\circ}\\\Rightarrow P_2\cos\theta=18-13\cos55^{\circ}\\\Rightarrow P_2\cos\theta=10.54\ \text{kg m/s}$

Momentum in the y direction

$P_1\sin55=P_2\sin\theta\\\Rightarrow P_2\sin\theta=13\sin55^{\circ}\\\Rightarrow P_2\sin\theta=10.64\ \text{kg m/s}$

$(P_2\cos\theta)^2+(P_2\sin\theta)^2=P_2^2\\\Rightarrow P_2=\sqrt{10.54^2+10.64^2}\\\Rightarrow P_2=14.98\ \text{kg m/s}$

The pin's resultant velocity is $14.98\ \text{kg m/s}$

$P_2\sin\theta=10.64\\\Rightarrow \theta=sin^{-1}\dfrac{10.64}{14.98}\\\Rightarrow \theta=45.26^{\circ}$

The pin's resultant direction is $45.26^{\circ}$ below the horizontal or to the right.

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