The number of waves passing a fixed point per second is known as ______________.

1 answer:

5 0

<span>The number of waves passing a fixed point per second is known as frequency. The higher the number is, the greater is the frequency of the wave. The SI unit for wave frequency is the hertz (Hz).</span>

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7. A thin wire was wound 30 times closely over a boiling tube. The total length of the windings as measured was found to be 6.3m

faltersainse [42]

Answer:

Diameter of wire = 0.00021 meters

Explanation:

Given the following data;

Number of windings = 30

Length of windings = 6.3 mm to meters = 0.0063 meters

To find the diameter of the wire, we would use this mathematical expression;

Length of windings = number of windings * diameter of wire

Substituting the values into the expression, we have;

0.0063 = 30 * diameter of wire

Diameter of wire = 0.0063/30

Diameter of wire = 0.00021 meters

6 0

3 years ago

A 91.5 kg football player running east at 2.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft

pentagon [3]

Answer:

2.877 m/s

Explanation:

According to the laws of conservation of linear momentum,

the momentum of the moving objects before impact is equal to the momentum of the objects after impact (Assuming no external forces were applied)

Let both players are tackled and moving in V velocity

M and m - masses of the players
U and u - velocities of them respectively (both velocities are towards east direction )

momentum before impact = momentum after impact

→MU + →mu = →(M+ m )v

91.5 * 2.73 + 63.5 * 3.09 = (91.5 + 63.5) * V

→V = 2.877 m/s (To East)

3 0

3 years ago

Read 2 more answers

An antiproton is identical to a proton except it has the opposite charge, âˆ’e. To study antiprotons, they must be confined in a

Zigmanuir [339]

Answer:

Explanation:

We know that, the force responsible for circulating in circular path is the centripetal force given by the force on charged particle due to magnetic field.

Here the charge is antiproton is

p = -1.6 * 10⁻¹⁹C

the speed of proton is given by 1.5 * 10 ⁴ m/s

the magnetic field is B = 4.5 * 10⁻³T

we have force due to magnetic field is equal to centripetal force

Bqv = mv² / r

Bq = mv / r

$r = \frac{mv}{Bq} \\\\r=\frac{mv}{Bq} \\\\r=\frac{1.67 \times 10^-^2^7\times 1.5 \times 10^4}{4.5 \times 10^-^3\times 11.6\times 10^-^1^9} \\\\r=347.9\times 10^-^4\\\\r=3.479cm$