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yarga [219]
2 years ago
5

A 0.03 kg baby sea turtle moves across the sand toward the ocean at 0.3 m/s. What is her kinetic energy in Joules?

Physics
1 answer:
lina2011 [118]2 years ago
4 0

Answer:

.00135 j

Explanation:

K.E. = 1/2   m  v^2

       = 1/2 * .03 * .3^2 = .00135 j

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A load of mass 5kg is raised through a height of 2m. calculate the work done against (g=10mls)​
Illusion [34]

The work done against gravity is 100 J

Explanation:

The work done against gravity in order to lift an object is equal to the change in gravitational potential energy of the object:

W=mg\Delta h

where

m is the mass of the object

g is the acceleration of gravity

\Delta h is the change in height of the object

For the object in this problem, we have:

m = 5 kg

g=10 m/s^2

\Delta h = 2 m

Substituting into the equation,

W=(5)(10)(2)=100 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

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3 0
3 years ago
A diver leaves the end of a 4.0 m high diving board and strikes the water 1.3s later, 3.0m beyond the end of the board. Consider
shutvik [7]

Answer:

4.0 m/s

Explanation:

The motion of the diver is the motion of a projectile: so we need to find the horizontal and the vertical component of the initial velocity.

Let's consider the horizontal motion first. This motion occurs with constant speed, so the distance covered in a time t is

d=v_x t

where here we have

d = 3.0 m is the horizontal distance covered

vx is the horizontal velocity

t = 1.3 s is the duration of the fall

Solving for vx,

v_x = \frac{d}{t}=\frac{3.0 m}{1.3 s}=2.3 m/s

Now let's consider the vertical motion: this is an accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. The vertical position at time t is given by

y(t) = h + v_y t - \frac{1}{2}gt^2

where

h = 4.0 m is the initial height

vy is the initial vertical velocity

We know that at t = 1.3 s, the vertical position is zero: y = 0. Substituting these numbers, we can find vy

0=h+v_y t - \frac{1}{2}gt^2\\v_y = \frac{0.5gt^2-h}{t}=\frac{0.5(9.8 m/s^2)(1.3 s)^2-4.0 m}{1.3 s}=3.3 m/s

So now we can find the magnitude of the initial velocity:

v=\sqrt{v_x^2+v_y^2}=\sqrt{(2.3 m/s)^2+(3.3 m/s)^2}=4.0 m/s

4 0
3 years ago
A bald eagle is flying to the left with a speed of 34 meters
Shtirlitz [24]

Answer:

the speed after 3 seconds is 10 m/s

Explanation:

The computation of the speed is shown below:

As we know that

V = U  + at

Here,

U = 34 m/s

a =  - 8 m/s²

t = 3 Sec

V = velocity after 3 sec

V  = 34 + (-8)3

 = 34 - 24

 V = 10 m/s

Hence, the speed after 3 seconds is 10 m/s

4 0
2 years ago
The earth's tectonic plates are directly propelled by the convection in the __________.
frozen [14]

The missing word here is <u>Asthenosphere.</u><u> </u>

The convection in the asthenosphere directly propels the tectonic plates of the earth.


Did you know that the asthenosphere is thought to remain malleable because of heat from deep within the Earth? It is thought to be lubricating the earth's tectonic plates' undersides and enabling movement.


The older, denser portions of the lithosphere that are dragged downward in subduction zones are stored in the asthenosphere, according to the theory of plate tectonics.

The lithosphere above is stressed by convection currents, and the cracking that frequently results manifests as earthquakes.

Magma is forced upward through volcanic vents and spreading centers by convection currents produced within the asthenosphere, which also results in the formation of new crust.

Learn why properties of the asthenosphere are important: brainly.com/question/11484043

#SPJ4

3 0
1 year ago
A remote controlled car is moving in a vacant parking lot. The velocity of the car as a function of time is given by v= [5.00 m/
Volgvan
Maybe try A for your answer
5 0
3 years ago
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