The second one (4.1 kg ball)
This is because the mxv is greater than the other one.
For the 4.1kg ball, the force it’s moving on is 4.92N
As for the 3.2kg ball, it’s moving with a force of 0.9N. Much less than the other one.
Answer:
Since formula for current is
I = Q/t
or
Current = Charge / Time
to increase current, the charge must be increased per unit time.
Answer:
In hot gases , the atoms keeps colliding with each other and sometimes the energy liberated during collision takes the electron to a higher level,thus, .The object is a cloud of hot gas and finally the electron returns back emitting photon
Answer:
d) 12 V
Explanation:
Due to the symmetry of the problem, the potential (relative to infinity) at the midpoint of the square, is the same for all charges, provided they be of the same magnitude and sign, and be located at one of the corners of the square.
We can apply the superposition principle (as the potential is linear with the charge) and calculating the total potential due to the 4 charges, just adding the potential due to any of them:
V = V(Q₁) + V(Q₂) +V(Q₃) + V(Q₄) = 4* 3.0 V = 12. 0 V
So lets list out we have here:
velocity = 62 m/s
Force = 272 N
Mass = 0.058kg
In studying momentum you learn that the force multiplied by the change in time is equal to the change in momentum.
FΔt = Δp
FΔt = p(final) - p(initial)
The ball is orginally at rest so its momentum is zero because momentum = mass x velocity and if velocity is 0 then the whole equation goes to zero. So...
FΔt = p(final)
Isolating for Δt gives
Δt = p(final) / F
Δt = mv / F
Δt = (0.058)(62) / (272)
Δt = 0.013 seconds