All categories

3 years ago

The hypotenuse of a right triangle is 15cm, and the shorter leg is 9cm. Find the length of the other leg

Mathematics

2 answers:

pishuonlain [190]3 years ago

3 0

Hello!

If you add up the squares of the two legs, it will equal the square of the hypotenuse. As we already have the hypotenuse, we will subtract.

225-81=144

Now we find the square root.

√144=12

Therefore, the other leg is 12 cm long.

I hope this helps!

jasenka [17]3 years ago

3 0

Hello,

We apply the theorem of Pythagoras. Let x be the other side, y the hypotenuse and z the smallest side.

x² = y² - z²

x² = 15² - 9²

x² = 225 - 81 = 144

x = √(144) = 12 cm

Bye :)

You might be interested in

What is two thirds cubed

I am Lyosha [343]

Answer:

$\frac{8}{27}$

Step-by-step explanation:

When you cube a fraction, you cube the top and bottom. Cubing 2 gives us 8 and cubing 3 gives us 27. Their GCF is 1 so that is the simplest form.

5 0

3 years ago

Find 100,000 more than 3,489,234.

EastWind [94]

Answer:

The answer is 3,589,234

Step-by-step explanation:

Because it basically means addition meaning you just have to add it 3,489,234 + 100,000 gives you the answer

7 0

3 years ago

Which describes Myra's distance as time increases?

DaniilM [7]

Answer:

(A)increasing

Step-by-step explanation:

Given the time and total distance ran by Myra in the table below.

$\left|\begin{array}{c|c}Time(minutes)&Distance(miles)\\--&--\\0&0.0\\2&0.4\\4&0.8\\6&1.2\\8&1.6\end{array}\right|$

We observe that as time increases, Myra's distance also increases. It is the speed(0.2 miles per minute) which is constant.

Therefore Option A is the correct option.

3 0

3 years ago

Read 2 more answers

As infants grow from a toddler to a young adult, there may be times when they are ill and medication is needed. It is extremely

Alex17521 [72]

Answer:

Each age is 12 more than the last so the rate of change would be twelve.

Yes it is linear, every twelve pounds is 2.5 more millimeters of dosage.

7 0

3 years ago

Read 2 more answers

Use the Ratio Test to determine the convergence or divergence of the series. If the Ratio Test is inconclusive, determine the co

jeka57 [31]

Answer:

<h2>A. The series CONVERGES</h2>

Step-by-step explanation:

If $\sum a_n$ is a series, for the series to converge/diverge according to ratio test, the following conditions must be met.

$\lim_{n \to \infty} |\frac{a_n_+_1}{a_n}| = \rho$

If $\rho$ < 1, the series converges absolutely

If $\rho > 1$ , the series diverges

If $\rho = 1$ , the test fails.

Given the series $\sum\left\ {\infty} \atop {1} \right \frac{n^2}{5^n}$

To test for convergence or divergence using ratio test, we will use the condition above.

$a_n = \frac{n^2}{5^n} \\a_n_+_1 = \frac{(n+1)^2}{5^{n+1}}$

$\frac{a_n_+_1}{a_n} = \frac{{\frac{(n+1)^2}{5^{n+1}}}}{\frac{n^2}{5^n} }\\\\ \frac{a_n_+_1}{a_n} = {{\frac{(n+1)^2}{5^{n+1}} * \frac{5^n}{n^2}\$

$\frac{a_n_+_1}{a_n} = {{\frac{(n^2+2n+1)}{5^n*5^1}} * \frac{5^n}{n^2}\\$

aₙ₊₁/aₙ =

$\lim_{n \to \infty} |\frac{ n^2+2n+1}{5n^2}| \\\\Dividing\ through\ by \ n^2\\\\\lim_{n \to \infty} |\frac{ n^2/n^2+2n/n^2+1/n^2}{5n^2/n^2}|\\\\\lim_{n \to \infty} |\frac{1+2/n+1/n^2}{5}|\\\\$

note that any constant dividing infinity is equal to zero

$|\frac{1+2/\infty+1/\infty^2}{5}|\\\\$

$\frac{1+0+0}{5}\\ = 1/5$

$\rho = 1/5$

Since The limit of the sequence given is less than 1, hence the series converges.

5 0

3 years ago