Answer:
General Formulas and Concepts:
<u>Algebra I</u>
<u>Calculus</u>
Antiderivatives - integrals/Integration
Integration Constant C
U-Substitution
Integration Property [Multiplied Constant]:
Trig Integration:
Step-by-step explanation:
<u>Step 1: Define</u>
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<u />
<u>Step 2: Integrate Pt. 1</u>
- [Integral] Factor fraction denominator:
- [Integral] Integration Property - Multiplied Constant:
<u>Step 3: Identify Variables</u>
<em>Set up u-substitution for the arctan trig integration.</em>
<u>Step 4: Integrate Pt. 2</u>
- [Integral] Substitute u-du:
- [Integral] Trig Integration:
- [Integral] Simplify:
- [integral] Multiply:
- [Integral] Back-Substitute:
Topic: AP Calculus AB
Unit: Integrals - Arctrig
Book: College Calculus 10e
the answer to this equation is 120
Answer: that would be 76% hope that helps
Step-by-step explanation:
Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line is
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given
Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.
Substituting m1 we get m2 as
Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line is
Answer:
No Solution
Step-by-step explanation:
8x+15=8x (2 times 4x equals 8x)
15=0 (Move the 8x to the other side)
No Solution (15 can't be equal to 0)