Answer:
2(3x + 7)(2x - 1)
Step-by-step explanation:
You can see it a little easier if you take out a common factor of 2
2(6x^2 + 11x - 7)
The 6 leaves you with a lot of factors, the 7 does not. It only has 2 factors.
Let 6 factor into 2 and 3 and the 7 into 7 and 1
2(3x - 1 )(2x + 7)
Now remove the brackets.
2(6x^2 + 21x - 2x - 7) This obviously does not work but we'll combine like terms anyway.
2(6x^2 + 19x - 7)
So we'll try it again
2(3x + 7)(2x - 1)
2(6x^2 + 14x - 3x - 7) Looks like we have it.
2(6x^2 + 11x - 7)
So the right factors are
2(3x + 7)(2x - 1)
Answer:
No.
Step-by-step explanation:
The definition of a function is that every output (x) has only one input (y).
Here -3 gives two different outputs which contradicts the definition of a function.
9514 1404 393
Answer:
0, 1, 2, 3
Step-by-step explanation:
The set of absolute values of integers is the set of non-negative integers. The four smallest values of the set are ...
0, 1, 2, 3
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Answer:
50% probability that on a randomly selected day during this period, a unit of currency B was worth more than 1.094 units of currency A.
Step-by-step explanation:
The Empirical Rule(68-95-99.7 rule) states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 1.094
Standard deviation = 0.013
a) What is the probability that on a randomly selected day during this period, a unit of currency B was worth more than 1.094 units of currency A?
The normal distribution is symmetric, which means that 50% of the units of currency B are more than 1.094 of currency A and 50% are below.
So
50% probability that on a randomly selected day during this period, a unit of currency B was worth more than 1.094 units of currency A.
