Answer:

Step-by-step explanation:
Let,
Now, us simplify the given differential equation and write it in terms of D,

or, 
or, 
We have our auxiliary equation:

or, 
or, 
Therefore our solution is,

and, 
Applying the boundary conditions, we get,


Solving them gives us,

Hence,

Answer: D. between 4.79 and 4.8
Step-by-step explanation:
The square root of 23 (√23) is 4.79583152331. We can obviously eliminate A and B. C and D is left. C is wrong because if we approximate the square root of 23, which is 4.79583152331, we get 4.79. 4.79 > 4.78, so it can't be C. Hope this helps :)
The answer is x= - 11/ 16
You can check this by plugging in x for -11/16
Answer:
x+1
Step-by-step explanation: