The area of a playground is 204 yd^2 the width of thr playground is 5 yd longer that its length what the length and the width of the playground
1 answer:
W= width= L+5 L= length Area= 204 Area= LW 204 square yards= LW substitute w=L+5 for w 204= (L)(L+5) 204= L^2 + 5L subtract 204 from both sides 0= L^2 + 5L - 204 factor 0= (L+17)(L-12) 0= L+17 -17= L 0= L-12 12 yards= L WIDTH Since the area cannot be a negative number, we'll use L=12 to find the width. w=L+5 w=12+5 w=17 yards CHECK: 204=(12)(17) 204=204 ANSWER: The length is 12 yards and the width is 17 yards. Hope this helps! :)
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