Hello!
To determine [H₃O⁺], we need to apply the Henderson-Hasselback equation, since this is a case of an acid and its conjugate base:
![pH=pKa+log( \frac{[A^{-}] }{[HA]} )](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%20%7D%7B%5BHA%5D%7D%20%29)

Now, we use the definition of pH and clear [H₃O⁺] from there:
![pH=-log[H_3O^{+}]](https://tex.z-dn.net/?f=pH%3D-log%5BH_3O%5E%7B%2B%7D%5D%20)
![[H_3O^{+}] = 10^{-pH} =10^{-3,84}=0,00014 M](https://tex.z-dn.net/?f=%20%5BH_3O%5E%7B%2B%7D%5D%20%3D%2010%5E%7B-pH%7D%20%3D10%5E%7B-3%2C84%7D%3D0%2C00014%20M)
So, the [H₃O⁺] concentration is
0,00014 M
Have a nice day!
Answer:
40% of registered voters voted
Explanation:
3200 out of 8000,
or :
3200 / 8000
= 0.4
0.4 x 100 = 40
40% of registered voters voted
Some fuels are used to better suit vehicles, while other types of fuels are used to reduce carbon emmision, e.t.c.
I couldn't really find anything about the growth time but it does say that it could remain viable in soil for up to 40 years
<span>Answer:
if it was planar the center of the negative forces and the center of the positive forces would be at the same place, meaning no di-poles would form so it wouldnt be polar. as it is polar it therefore cannot be planar.
the neagative center(pole) is above the the positive one due to the pair of unbonded electrons.</span>