How would you compare a health care system in Ancient Egypt and a interdisciplinary health care team?

Both the National Fire Academy and Iowa formulas calculate the flow requirement for structures that are __________ percent invol

emmainna [20.7K]

Answer:

100

Explanation:

7 0

2 years ago

Question 6 (3 points)

olga55 [171]

Answer:

Explanation:

Given parameters:

Molarity of KOH = 0.26M

Volume of H₂SO₄ = 19.76mL

Molarity of H₂SO₄ = 0.20M

Unknown:

Volume of KOH = ?

Solution:

This is a neutralization reaction in which an acid reacts with a base to produce salt and water:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

We solve from the known to the unknown in the reaction.

The known is the acid and from there we can find the number of moles of the acid to be completely neutralized:

Number of moles of acid = molarity x volume

Number of moles of acid = 19.76 x 0.20 = 3.95mol

From the balanced reaction equation:

1 mole of acid reacts with 2 moles of the bases KOH

3.95mole of acid would react with 3.95moles x 2 of the base

Number of moles of reacting base = 7.90moles

To find the volume of base;

Volume of base = $\frac{number of moles of base}{molarity}$

Volume = $\frac{7.90}{0.26}$ = 30.40mL

Learn more:

Neutralization brainly.com/question/6447527

#learnwithBrainly

8 0

3 years ago

The combustion of hydrogen-oxygen mixtures is used to produce very high temperatures (ca. 2500 °C) needed for certain types of w

tangare [24]

Answer:

1360kJ are evolved

Explanation:

When 1mole of H2 reacts with 1/2 moles O2 producing 1 mole of water and 241.8kJ.

To solve this question we need to find the limiting reactant knowing were added 90g of H2 and 90g of O2 as follows:

<em>Moles H2 -Molar mass: 2g/mol-</em>

90g H2 * (1mol / 2g) = 45 moles

<em>Moles O2 -Molar mass: 32g/mol-</em>

90g * (1mol / 32g) = 2.81moles

For a complete reaction of 2.81 moles of O2 are needed:

2.81 moles O2 * (1mol H2 / 1/2 mol O2) = 5.62 moles H2

As there are 45 moles, H2 is the excess reactant and O2 the limiting reactant.

As 1/2 moles O2 produce 241.8kJ, 2.81 moles will produce:

2.81 moles O2 * (241.8kJ / 1/2moles O2) =

<h3>1360kJ are evolved</h3>

6 0

2 years ago

What volume in milliliters of 1.420 M sulfuric acid is needed to neutralize 3.209 g of aluminum hydroxide 3 H 2 SO 4 (aq)+2 Al(O

nadya68 [22]

Answer:

$V=43.46mL$

Explanation:

Hello!

In this case, since the reaction between sulfuric acid and aluminum hydroxide is:

$3H_2SO_4+2Al(OH)_3\rightarrow Al_2(SO_4)_3+6H_2O$

Whereas the ratio of sulfuric acid to aluminum hydroxide is 3:2; thus, we first compute the moles of sulfuric acid that complete react with 3.209 g of aluminum hydroxide:

$n_{H_2SO_4}=3.209gAl(OH)_3*\frac{1molAl(OH)_3}{78.00gAl(OH)_3} *\frac{3molH_2SO_4}{2molAl(OH)_3} \\\\n_{H_2SO_4}=0.0617molH_2SO_4$

Then, given the molarity, it is possible to obtain the milliliters as follows:

$V=\frac{n}{M}=\frac{0.0617mol}{1.420mol/L}*\frac{1000mL}{1L}\\\\V=43.46mL$

Best regards!

7 0

2 years ago

Write a balanced equation for the neutralization of the following.

babunello [35]

Answer:the answer is B.) H2O3(aq) and Mg (OH)2(s)

Explanation:

4 0

3 years ago