Answer: 0.7748
Step-by-step explanation:
Given : Number of bit bulls at the pound = 18
Number of pit bulls have attacked another dog in the last year =4
The proportion of pit bulls have attacked another dog in the last year:
Number of the pit bulls selected = 6
The probability of that none of the pit bulls in Joe's group attacked another dog last year : 
By using binomial , the probability that at least one of the pit bulls in Joe's group attacked another dog last year is given by :-

Hence, the required probability = 0.7748
Answer:
steps below
Step-by-step explanation:
3.2.1 AD = DB* sin 2 = DB * sin θ .. DE // AB ∠2= θ ... (1)
By laws of sines: DB / sin ∠5 = x / sin ∠4
∠4 = θ-α ∠5 = 180°-<u>∠1</u>-∠4 = 180°-<u>∠3</u>-∠4 = 180°-(90°-θ)-(θ-α)) = 90°+α
DB = (x*sin ∠5)/sin (θ-α)
= (x* sin (90°+α)) / sin (θ-α)
AD = DB*sinθ
= (x* sin (90°+α))*sinθ / sin (θ-α)
= x* (sin90°cosα+cos90°sinα)*sinθ / sin (θ-α) .... sin90°=1, cos90°=0
= x* cosα* sinθ / sin (θ-α)
3.2.2 Please apply Laws of sines to calculate the length
Consecutive exterior angles
Answer:23/50
Step-by-step explanation:its 46/100 but it simplifies to 23/50 hope this helps god bless
Answer:
x = 12
Step-by-step explanation:
Angle Bisector Theorem: PS / PQ = RS / QR
24/14 = x/7
cross-multiply:
14x = 168
x = 12