How many mL of 6.00M HCl are needed to neutralize 50.00mL of 3.25M NaOH?

1 answer:

5 0

Answer:

0.027L or 27.1mL

Step-by-step explanation:

v1m1=v2m2

v1x6M=.05Lx3.25M

V1=0.027L or 27.1mL

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