The number of kilowatts used by an individual to operate his appliances is determined as 12.1 kWh.
<h3>
Average daily power consumption</h3>
The average daily power consumption is the amount of electric energy consumed by an individual on a daily rate.
The average daily power consumption of individuals in USA is 12,100 W-hr.
<h3>Converting watts to kilowatts</h3>
E = 12,100 Whr/1000
E = 12.1 kWh
Thus, the number of kilowatts used by an individual to operate his appliances is determined as 12.1 kWh.
Learn more about power here: brainly.com/question/13881533
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Hope it helped you.
My name is Charlie.
Today this question is about science,or chemistry.
A. Acceleration is a correct answer. Acceleration is a rate of change in velocity.
It change in velocity/change in time. Next, to slope will be indicated by the acceleration.
B Change in position is a incorrect answer.
C. Velocity is a incorrect answer. Velocity is a displacement of an object during a specific unit of time. It can used two measurements are needed to determine velocity. It displacement or by the time. Displacement it includes a direction, so the velocity will also includes a direction. It can used speed with direction. Velocity it can be average velocity or an instantaneous velocity.
-Charlie
Have a great day!
Thanks!
Supposing velocity is speed and direction, and momentum is mass*velocity, if the velocity increases by a factor of 5, then so should the momentum regardless of the whole space thing.
The circuit change when the wire is added will see a short circuit occur and makes bulbs 1 and 2 turn off but keeps bulbs 3 and 4 lit. Option D. This is further explained below.
<h3>
How does the circuit change when the wire is added?</h3>
Generally, Electronic circuits consist of a series of interconnected parts that form a closed loop through which electricity may flow.
In conclusion, If two wires are linked together, a short circuit will develop, cutting power to bulbs 1 and 2. But there is no impact on bulbs 3 and 4. There is no problem with bulbs 3 and 4.
Read more about circuit
brainly.com/question/21505732
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Answer:
The moment of inertia about an axis through the center and perpendicular to the plane of the square is
![I_s = \frac{Ma^2}{3}](https://tex.z-dn.net/?f=I_s%20%3D%20%20%5Cfrac%7BMa%5E2%7D%7B3%7D)
Explanation:
From the question we are told that
The length of one side of the square is ![a](https://tex.z-dn.net/?f=a)
The total mass of the square is ![M](https://tex.z-dn.net/?f=M)
Generally the mass of one size of the square is mathematically evaluated as
![m_1 = \frac{M}{4}](https://tex.z-dn.net/?f=m_1%20%3D%20%5Cfrac%7BM%7D%7B4%7D)
Generally the moment of inertia of one side of the square is mathematically represented as
![I_g = \frac{1}{12} * m_1 * a^2](https://tex.z-dn.net/?f=I_g%20%3D%20%20%5Cfrac%7B1%7D%7B12%7D%20%20%2A%20%20m_1%20%2A%20a%5E2)
Generally given that
it means that this moment inertia evaluated above apply to every side of the square
Now substituting for ![m_1](https://tex.z-dn.net/?f=m_1)
So
![I _g= \frac{1}{12} * \frac{M}{4} * a^2](https://tex.z-dn.net/?f=I%20_g%3D%20%20%5Cfrac%7B1%7D%7B12%7D%20%20%2A%20%20%5Cfrac%7BM%7D%7B4%7D%20%2A%20a%5E2)
Now according to parallel-axis theorem the moment of inertia of one side of the square about an axis through the center and perpendicular to the plane of the square is mathematically represented as
![I_a = I_g + m [\frac{q}{2} ]^2](https://tex.z-dn.net/?f=I_a%20%3D%20%20I_g%20%2B%20m%20%5B%5Cfrac%7Bq%7D%7B2%7D%20%5D%5E2)
=> ![I_a = I_g + {\frac{M}{4} }* [\frac{q}{2} ]^2](https://tex.z-dn.net/?f=I_a%20%3D%20%20I_g%20%2B%20%7B%5Cfrac%7BM%7D%7B4%7D%20%7D%2A%20%5B%5Cfrac%7Bq%7D%7B2%7D%20%5D%5E2)
substituting for ![I_g](https://tex.z-dn.net/?f=I_g)
=> ![I_a = \frac{1}{12} * \frac{M}{4} * a^2 + {\frac{M}{4} }* [\frac{q}{2} ]^2](https://tex.z-dn.net/?f=I_a%20%3D%20%20%5Cfrac%7B1%7D%7B12%7D%20%20%2A%20%20%5Cfrac%7BM%7D%7B4%7D%20%2A%20a%5E2%20%2B%20%7B%5Cfrac%7BM%7D%7B4%7D%20%7D%2A%20%5B%5Cfrac%7Bq%7D%7B2%7D%20%5D%5E2)
=> ![I_a = \frac{Ma^2}{48} + \frac{Ma^2}{16}](https://tex.z-dn.net/?f=I_a%20%3D%20%5Cfrac%7BMa%5E2%7D%7B48%7D%20%2B%20%5Cfrac%7BMa%5E2%7D%7B16%7D)
=> ![I_a = \frac{Ma^2}{12}](https://tex.z-dn.net/?f=I_a%20%3D%20%5Cfrac%7BMa%5E2%7D%7B12%7D)
Generally the moment of inertia of the square about an axis through the center and perpendicular to the plane of the square is mathematically represented as
![I_s = 4 * I_a](https://tex.z-dn.net/?f=I_s%20%3D%204%20%2A%20I_a)
=> ![I_s = 4 * \frac{Ma^2}{12}](https://tex.z-dn.net/?f=I_s%20%3D%204%20%2A%20%5Cfrac%7BMa%5E2%7D%7B12%7D)
=> ![I_s = \frac{Ma^2}{3}](https://tex.z-dn.net/?f=I_s%20%3D%20%20%5Cfrac%7BMa%5E2%7D%7B3%7D)