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4 years ago

A horse began running due east and covered 25 km in 4.0 hr. What is the average velocity of the horse?

Physics

2 answers:

LenKa [72]4 years ago

4 0

Answer:

B) $v = 6.25\frac{km}{hr}$ due east

Explanation:

Conceptual analysis

The average speed (v) is defined as the relationship between the displacement (d) that a body made and the total time (t) it took to perform it and is calculated by the following formula:

$v = \frac{d}{t}$ Formula (1)

v: velocity in m/s

d: Displacement (m)

t: Time (s)

Known data

We know the following data

d = 25 km

t = 4.0 hr

Problem development

We replace data in formula (1):

$v =\frac{25km}{4hr}$

$v = 6.25\frac{km}{hr}$

Darina [25.2K]4 years ago

3 0

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3 years ago

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Answer:

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$t=t_o\sqrt{1-\dfrac{v^2}{c^2}}\\\Rightarrow 90=2.54\times 10^7\sqrt{1-\dfrac{v^2}{c^2}}\\\Rightarrow \dfrac{90^2}{(2.54\times 10^7)^2}=1-\dfrac{v^2}{c^2}\\\Rightarrow 1-\dfrac{90^2}{(2.54\times 10^7)^2}=\dfrac{v^2}{c^2}\\\Rightarrow v=c\sqrt{1-\dfrac{90^2}{(2.54\times 10^7)^2}}$

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