Answer:
surface charge density on each sphere is 
C
Explanation:
given data
radius of smaller sphere = 5 cm
radius of larger sphere is 12 cm
electric field at surface of larger sphere = 660 kV/m = 660 × 1000 v/m
solution
we apply here electric field formula that is express as
E = 
.................1
put here value
660000 = 
Q1 = 1056 × 
and
here field inside a conductor is zero so that electric potential ( V ) is constant
..................2
so Q2 will be
Q2 = 
Q2 = C
Answer: 1.77 s
Explanation: In order to solve this problem we have to use the kinematic equation for the position, so we have:
xf= xo+vo*t+(g*t^2)/2 we can consider the origin on the top so the xo=0 and xf=29 m; then
(g*t^2)/2+vo*t-xf=0 vo is the initail velocity, vo=7.65 m/s
then by solving the quadratric equation in t
t=1.77 s
Some examples of projective tests are the Rorschach Inkblot Test, the Thematic Apperception Test (TAT), the Contemporized-Themes Concerning Blacks test, the TEMAS (Tell-Me-A-Story), and the Rotter Incomplete Sentence Blank (RISB).
Some examples of projective tests are the Rorschach Inkblot Test, the Thematic Apperception Test (TAT), the Contemporized-Themes Concerning Blacks test, the TEMAS (Tell-Me-A-Story), and the Rotter Incomplete Sentence Blank (RISB).
Answer:
The answer to your question should be D.
Explanation:
reactants are on the laft side of arrow and products are on right side of arrow
