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attashe74 [19]
3 years ago
11

A 10.0 N package of whole wheat flour is suddenly placed on the pan of a scale such as you find in grocery stores. The pan is su

pported from below by a vertical spring of force constant 395 N/m. If the pan has negligible weight, find the maximum distance the spring will be compressed if no energy is dissipated by friction.
Physics
1 answer:
inna [77]3 years ago
7 0

Answer:

0.025 m

Explanation:

From the question,

Applying Hook's law

F = ke................... Equation 1

Where F = Force, k = spring constant of the scale, e = maximum distance at which the spring will compress.

make e the subject of the equation

e = F/k....................... Equation 2

Given: F = 10 N, e = 395 N/m

Substitute these values into equation 2

e = 10/395

e = 0.025 m

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A circular loop of radius r carries a current i. at what distance along the axis of the loop is the magnetic field one-half its
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At r = 0.766 R the magnetic field intensity will be half of its value at the center of the current carrying loop.

We have a circular loop of radius ' r ' carrying current ' i '.

We have to find at what distance along the axis of the loop is the magnetic field one-half its value at the center of the loop.

<h3>What is the formula to calculate the Magnetic field intensity due to a current carrying circular loop at a point on its axis?</h3>

The formula to calculate the magnetic field intensity due to a current carrying ( i ) circular loop of radius ' R ' at a distance ' x ' on its axis is given by -

B(x) = \frac{\mu_{o} iR^{2} }{2(x^{2} +R^{2})^{\frac{3}{2} } }

Now, for magnetic field intensity at the center of the loop can calculated by putting x = 0 in the above equation. On solving, we get -

B(0) = \frac{\mu_{o} i}{2R}

Let us assume that the distance at which the magnetic field intensity is one-half its value at the center of the loop be ' r '. Then -

\frac{\mu_{o} iR^{2} }{2(r^{2} +R^{2})^{\frac{3}{2} } } = \frac{1}{2} \frac{\mu_{o}i }{2R}

2R^{3} = (r^{2} +R^{2} )^{\frac{3}{2} }

4R^{6} = (r^{2} +R^{2} )^{3}

r^{2} =0.587R^{2}

r = 0.766R

Hence, at r = 0.766 R - the magnetic field intensity will be half of its value at the center of the current carrying loop.

To solve more questions on magnetic field intensity, visit the link below-

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A ski resort consists of a few chairlifts and several interconnected downhill runs on the side of a mountain, with a lodge at th
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<h3>What is Kirchhoff's loop rule?</h3>

Kirchhoff's loop rule is also referred to as Kirchhoff's second law or Kirchhoff's voltage law, and it states that the algebraic sum of all the electric potential differences around any closed loop is equal to zero.

<h3>How to connect two runs in series?</h3>

Since the chairlifts are analogous to batteries, and the runs are analogous to resistors, the two runs would represent resistors that are connected in series with the lift, which represents the battery. Similarly, these three runs can also be connected in parallel by altering the positions of the runs with the battery.

For this ski resort, it ultimately implies that the total number of lifts that are used in any closed loop would be equal to zero in accordance with Kirchhoff's loop rule.

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7 0
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ch4aika [34]

Answer:

1:by standing with one feet

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Explanation:

1: by standing with one feet

2:by standing with ur toes

Pressure is inversely proportional to area, the little the area, the more the pressure.the bigger the area,the lesser the pressure

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