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Bess [88]
3 years ago
7

A 1500 kg car originally moving at 10 m/s crashes into a wall and comes to rest in 0.25 s. What is the magnitude of the impulse

given to the car?
a. 37.5 kg m/s
b. 150 kg m/s
c. 15,000 kg m/s
d. 60,000 kg m/s
Physics
1 answer:
kirill [66]3 years ago
6 0

Answer:

Option C

Explanation:

Impulse is the change in momentum in an object hence given by

Impulse=F∆t

Impulse=∆p=m(v-u)

Here, F is force applied, t is rime, m is mass, v is final velocity and u is initial velocity

Given that the question has time but no magnitude of the force, we use the sexond equation.

Taking forward velocity as negative then u=-10 m/s, also since the car comes to rest, final velocity is 0 m/s. Substititing mass with 1500 kgs then

Impulse=1500(0--10)=15000 kg.m/s

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A charge of 8.4*10^-4 moves at an angle of 35 degrees to a magnetic field that has a field strentgh of 6.7
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The force on a charged particle in a magnetic field is given by

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If i have a kinematic equation vf^2=vi^2-2*a(xf-xi), how can i solve for xi step by step
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