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Leya [2.2K]
3 years ago
14

Which would be considered a substance? Element, Compound, Mixture.

Chemistry
1 answer:
Romashka [77]3 years ago
3 0

Answer:

MIXTURE , ELEMENT AND SUBSTANCE

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If two clear liquids are mixed and a precipitate formed, what has probably happened?
White raven [17]
It will probably turned into a gumy
8 0
3 years ago
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Explain why it is harder to remove an inner shell electrons than a valence electron from an atom
VMariaS [17]
<span> It makes sense that an inner shell electron would be tougher to remove than a valence electron because the inner shell electron is closer to the positive nucleus of the atom. Seeing as an electron caries a negative charge it would be too attracted to the positive core to leave readily. Also, the inner shell electrons are constantly repelling electrons outside of it's energy level (however the reason these electrons outside innershell energy levels don't simply fly away is the charge of the positive core overcomes the smaller charges of the comparably negligible inner shell electrons, but that repulsion is still there so keep that in mind) </span>
6 0
3 years ago
It is known that the kinetics of recrystallization for some alloy obey the Avrami equation andthat the value of n in the exponen
Paul [167]

Answer:

rate of recrystallization = 4.99 × 10⁻³ min⁻¹

Explanation:

For Avrami equation:

y = 1-e ^{(-kt^n)} \\ \\ e^{(-kt^n)} = 1-y\\ \\ -kt^n = In(1-y) \\ \\ k = \dfrac{-In(1-y)}{t^n}

To calculate the value of k which is a dependent variable for the above equation ; we have:

k = \dfrac{-In(1-0.40)}{200^{2.5}}

k = 9.030 \times 10 ^{-7}

The time needed for 50% transformation can be determined as follows:

y = 1-e ^{(-kt^n)} \\ \\ e^{(-kt^n)} = 1-y\\ \\ -kt^n = In(1-y) \\ \\ t =[ \dfrac{-In(1-y)}{k}]^{^{1/n}}

t_{0.5} =[ \dfrac{-In(1-0.4)}{9.030 \times 10^{-7}}]^{^{1/2.5}}

= 200.00183 min

The rate of reaction for Avrami equation is:

rate = \dfrac{1}{t_{0.5}}

rate = \dfrac{1}{200.00183}

rate = 0.00499 / min

rate of recrystallization = 4.99 × 10⁻³ min⁻¹

8 0
3 years ago
When 35.0 mL of 0.400 M hydrobromic acid and 35.0 mL of 0.400 M ammonia are combined, the pH of the resulting solution will be :
Kay [80]

Answer:

B. Equal to 7.

Explanation:

Hydrobromic acid is a strong acid that decreases pH and ammonia is a strong base that increases pH.

As the initial pH of water is 7,0 the addition of 35.0mL of 0.400M HBr will produce a pH less than 7,0. But, the same effect of decreasing pH is reverted for the addition of 35.0mL of 0.400M HNO3.

That means the net effect of the two addition is to have a pH:

B. Equal to 7.

I hope it helps!

3 0
3 years ago
Sulfur (S) = 32, and of oxygen (O) = 16.
olganol [36]

Answer:

It should be 115.5 amu but you didnt type that as an answer choice so...

Explanation:

Bruh all you had to do was add oxygen and sulfur and subtract from the total to get your answer :D.

5 0
3 years ago
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