Answer: The mass of ester produced would be, 7.92 grams.
Explanation : Given,
Mass of butanoic acid = 7.70 g
Molar mass of butanoic acid = 88 g/mol
Molar mass of ethyl butyrate = 116 g/mol
First we have to calculate the moles of butanoic acid.
Now we have to calculate the moles of
The balanced chemical equation is:
From the balanced reaction we conclude that
As, 1 mole of react to give 1 mole of
So, 0.0875 mole of react to give 0.0875 mole of
Now we have to calculate the mass of
To calculate the amount of ester formed When the yield 78.0 % is calculated as follows:
Theoretical yield = 10.15 g
Now put all the given values in this formula, we get:
Therefore, the mass of ester produced would be, 7.92 grams.