Solve the equation 0.1x+7=2

Whats 7(35+5) i need it for my sexth grade exam tommorow

ki77a [65]

Answer:

280

Good luck on your exam tomorrow! :-)

Step-by-step explanation:

8 0

3 years ago

What is the distance between (-9, -6)(−2,−2)

Tamiku [17]

65=8.06225774 this is the distance

6 0

4 years ago

Read 2 more answers

Assume that foot lengths of women are normally distributed with a mean of 9.6 in and a standard deviation of 0.5 in.a. Find the

Makovka662 [10]

Answer:

a) 78.81% probability that a randomly selected woman has a foot length less than 10.0 in.

b) 78.74% probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

c) 2.28% probability that 25 women have foot lengths with a mean greater than 9.8 in.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 9.6, \sigma = 0.5$ .

a. Find the probability that a randomly selected woman has a foot length less than 10.0 in

This probability is the pvalue of Z when $X = 10$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{10 - 9.6}{0.5}$

$Z = 0.8$

$Z = 0.8$ has a pvalue of 0.7881.

So there is a 78.81% probability that a randomly selected woman has a foot length less than 10.0 in.

b. Find the probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

This is the pvalue of Z when X = 10 subtracted by the pvalue of Z when X = 8.

When X = 10, Z has a pvalue of 0.7881.

For X = 8:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{8 - 9.6}{0.5}$

$Z = -3.2$

$Z = -3.2$ has a pvalue of 0.0007.

So there is a 0.7881 - 0.0007 = 0.7874 = 78.74% probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

c. Find the probability that 25 women have foot lengths with a mean greater than 9.8 in.

Now we have $n = 25, s = \frac{0.5}{\sqrt{25}} = 0.1$ .

This probability is 1 subtracted by the pvalue of Z when $X = 9.8$ . So:

$Z = \frac{X - \mu}{s}$

$Z = \frac{9.8 - 9.6}{0.1}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772.

There is a 1-0.9772 = 0.0228 = 2.28% probability that 25 women have foot lengths with a mean greater than 9.8 in.

5 0

4 years ago

Find the 5 number summary for the data shown x 3.1 10.2 12 12.1 12.2 15.3 27.9 30

Kazeer [188]

Answer:

Min. 1st Qu. Median Mean 3rd Qu. Max.

3.10 11.55 12.15 15.35 18.45 30.00

Step-by-step explanation:

The five-number summary includes five things that are:

1. Minimum Value

2. First Quartile (Q₁)

3. Median

4. Third Quartile (Q₃)

5. Maximum Value

So,

1. Minimum Value = 3.10

It can be found by arranging the data in ascending order, the first value we will get is the minimum value.

2. First Quartile is the middle value between Minimum value and Median of data after arranging data in ascending order.

First Quartile (Q₁) = 11.55

3. Median is the middle value of the data after arranging them in ascending order.

Median = 12.15

4. The third Quartile is the middle value between Median and Maximum Value of data after arranging data in ascending order.

Third Quartile (Q₃) = 18.45

5. Maximum Value is the largest value of the data or is the last value after arranging the data in ascending order.

Maximum Value = 30.

Percentiles are mostly use in very large data. Here n percent of data shows the nth percentile.

5 0

4 years ago

What is this in standard form (2*1)+(6*1/1000)

neonofarm [45]

Answer:

2.006

Step-by-step explanation:

2*1 = 2

6*1 = 6/1000 = 0.006 + 2 = 2.006

Mark as brainliest PLZ! It will make my day! Thank you!

Visit my church's website at fbcinterlaken.org if you want to learn more about God!

8 0

3 years ago

Solve the equation 0.1x+7=2​

Solve the equation 0.1x+7=2