Answer:
dy/dt = - (1/5) ft/s = - 0.2 ft/s
Step-by-step explanation:
Given
L = 5 ft
Qin = 25 ft³/s
Qout = 30 ft³/s
h = 10 ft
dy/dt = ?
We can apply the relation
ΔQ = Qint - Qout = 25 ft³/s - 30 ft³/s
⇒ ΔQ = - 5 ft³/s
Then we use the formula
Q = v*A
where Q = ΔQ, A = L² is the area of square base and v = dy/dt is the rate of change in the depth of the solution in the tank
⇒ ΔQ = (dy/dt)*L²
⇒ dy/dt = ΔQ/L²
⇒ dy/dt = (- 5 ft³/s)/(5 ft)²
⇒ dy/dt = - (1/5) ft/s = - 0.2 ft/s
A rule of polygons is that the sum<span> of the </span>exterior angles<span> always equals 360 degrees, but lets prove this for a regular </span>octagon<span> (8-sides). First we must figure out what </span>each<span>of the interior </span>angles<span> equal. To do this we use the </span>formula<span>: ((n-2)*180)/n where n is the number of sides of the polygon</span>
Slope-intercept form is y=mx+b. our goal is to get y by itself on one side of the equation.
2x-3y+1=0
2x+1=3y
3y=2x+1
y=(2/3)x+1/3
That is the same function but in slope-intercept form.
