The length of AD is 32 feet
Step-by-step explanation:
An architect is sketching a blueprint of a patio for a new fence
- On the blueprint, C is the midpoint of segment AD
- Point B is the midpoint of segment AC
- BC = 8 feet
We need to find the length of AD
A mid-point divides a line segments into two equal parts in length
∵ C is the mid-point of AD
- The mid-point C divides the line segments AD into two equal parts
∴ AC = CD
∵ B is the mid point of AC
∴ AB = BC
∵ BC = 8 feet
∴ AB = 8 feet
- AC contains AB and BC
∵ AC = AB + BC
∴ AC = 8 + 8 = 16
∵ AC = CD
∵ AC = 16
∴ CD = 16
- AD contains AC and CD
∵ AD = AC + CD
∴ AD = 16 + 16 = 32
The length of AD is 32 feet
Learn more:
You can learn more about the mid-point in brainly.com/question/3269852
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Answer:
C. (3x)^2 - (2)^2
Step-by-step explanation:
Each of the two terms is a perfect square, so the factorization is that of the difference of squares. Rewriting the expression to ...
(3x)^2 - (2)^2
highlights the squares being differenced.
__
We know the factoring of the difference of squares is ...
a^2 -b^2 = (a -b)(a +b)
so the above-suggested rewrite is useful for identifying 'a' and 'b'.
Here, "disjointed" signifiies that Event A and Event B are independent; neither outcome influences the other. In such a case, the union of A and B is given by the sum of the two probabilities P(A) and P(B).
Here, that sum is P(A or B) = 6/25 + 9/25, or 15/25, or 0.6.
Heyy merry christmas !
area of a triangle = base * height : 2
4 * 5 = 20 : 2 = 10
10 * 12triangles = 120cm^3
Answer: 3∛2
<u>Step-by-step explanation:</u>
First, factor 128 .... you need three common factors to bring one on the outside of the radical.
![\dfrac{3}{4}\sqrt[3]{128} \\\\\\=\dfrac{3}{4}\sqrt[3]{4\cdot 4\cdot 4\cdot 2} \\\\\\=\dfrac{3}{4}\cdot 4\sqrt[3]{2} \\\\\\=\large\boxed{3\sqrt[3]{2} }](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B4%7D%5Csqrt%5B3%5D%7B128%7D%20%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B3%7D%7B4%7D%5Csqrt%5B3%5D%7B4%5Ccdot%204%5Ccdot%204%5Ccdot%202%7D%20%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B3%7D%7B4%7D%5Ccdot%204%5Csqrt%5B3%5D%7B2%7D%20%5C%5C%5C%5C%5C%5C%3D%5Clarge%5Cboxed%7B3%5Csqrt%5B3%5D%7B2%7D%20%7D)
