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guapka [62]
3 years ago
15

What is the slope of (6,0) and (0,8)

Mathematics
1 answer:
Anna007 [38]3 years ago
8 0

Your answer is 0. The slope formula is m = (y2 - y1) / (x2 - x1). So you do 8-0=8. Then you do 0-6=-6 Then you get 8 over -6. Simplified: -one and one third. That is the answer!

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Which inequality represents this sentence? Seven plus five is greater than six plus two. A. 7 + 5 ≥ 6 + 2 B. 6 + 2 > 7 + 5 C.
Ainat [17]
The answer would be D

Hope this helps!
5 0
3 years ago
Read 2 more answers
How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?
BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:  

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}

Where n = 8 and r = 0,1....8

When r = 0

\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1

When r = 1

\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 2

\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8

When r = 3

\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 4

\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70

When r = 5

\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 6

\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28

When r = 7

\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 8

\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0
3 years ago
How can properties of operations be used to add expressions?
Gelneren [198K]
Use this. Hope it helps

7 0
3 years ago
What is the measure of side AB
kkurt [141]
16 because the AB side gotta be a little bit bigger than the two other sides
8 0
3 years ago
7 1/5 - 6 2/5= <br> a. 1 1/5<br> b. 1 4/5<br> c. 13 3/5<br> d. 4/5
stira [4]

Answer:

4/5

Step-by-step explanation:

Simplify the following:

7 + 1/5 - (6 + 2/5)

Put 6 + 2/5 over the common denominator 5. 6 + 2/5 = (5×6)/5 + 2/5:

7 + 1/5 - (5×6)/5 + 2/5

5×6 = 30:

7 + 1/5 - (30/5 + 2/5)

30/5 + 2/5 = (30 + 2)/5:

7 + 1/5 - (30 + 2)/5

30 + 2 = 32:

7 + 1/5 - 32/5

Put 7 + 1/5 - 32/5 over the common denominator 5. 7 + 1/5 - 32/5 = (5×7)/5 + 1/5 - 32/5:

(5×7)/5 + 1/5 - 32/5

5×7 = 35:

35/5 + 1/5 - 32/5

35/5 + 1/5 - 32/5 = (35 + 1 - 32)/5:

(35 + 1 - 32)/5

35 + 1 = 36:

(36 - 32)/5

| 3 | 6

- | 3 | 2

| 0 | 4:

Answer:  4/5

8 0
4 years ago
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