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Oksanka [162]
3 years ago
6

The volume of a cone is 180 in3. find a function that models the height h of the cone in terms of its radius r.

Mathematics
1 answer:
12345 [234]3 years ago
5 0

volume of a cone = (1/3)*pi*r^2*h
180 = pi(r^2)h
180/pi(r*2) = h

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Estimate the Value Of Each Expression to the nearest integer .
omeli [17]

Answer:

see below

Step-by-step explanation:

14. We can represent 1 as √1 and 2 as √4 and because 1 < 3 < 4, we know that √3 is in between 1 and 2. However, 3 is closer to 4 than it is to 1 so √3 is about 2.

15. Again, 3 is √9 and 4 is √16. 9 < 10 < 16 so √10 is in between 3 and 4, however, since 10 is closer to 9 as it is to 16, we know that √10 is about 3.

16. -4 = -√16 and -5 = -√25, since 16 < 22 < 25, we know that -√22 is in between -4 and -5 but 22 is closer to 25 so the answer is -5.

17. -10 = -√100 and -11 = -√121 so -√120 is in between -10 and -11. Since 120 is closer to 121, the answer is -11.

5 0
3 years ago
Solve using the quadratic formula 2x^2 + 7x - 15 = 0
marissa [1.9K]

Answer:

1.5 or -5

Step-by-step explanation:

2x²+7x-15=0

Divide by 2:

x²+7x/2-15/2=0

x=-7/2/2 ± √49/4(4)+15/2

  =-7/4 ± √49/16+120/16

  =-7/4± √169/16=-7/4 ±13/4

  =6/4 or -20/4

   =1.5 or -5

3 0
3 years ago
A bin contains 25 light bulbs, 5 of which are in good condition and will function for at least 30 days, 10 of which are partiall
Ira Lisetskai [31]

Answer:

The probability that it will still be working after one week is \frac{1}{5}

Step-by-step explanation:

Given :

Total number of bulbs = 25

Number of bulbs which are good condition and will function for at least 30 days = 5

Number of bulbs which are partially defective and will fail in their second day of use = 10

Number of bulbs which are totally defective and will not light up = 10

To find : What is the probability that it will still be working after one week?

Solution :

First condition is a randomly chosen bulb initially lights,

i.e. Either it is in good condition and partially defective.

Second condition is it will still be working after one week,

i.e. Bulbs which are good condition and will function for at least 30 days

So, favorable outcome is 5

The probability that it will still be working after one week is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

\text{Probability}=\frac{5}{25}

\text{Probability}=\frac{1}{5}

5 0
3 years ago
If LM = 20 cm, and PQ = 16 cm, what is the length of RM, in centimeters?
LuckyWell [14K]

Answer:

RM = 12 cm

Step-by-step explanation:

a^{2} + b^{2} = c^{2}

Assuming 20 is the hypotenuse cus there is no picture:

a^{2} + 16^{2} = 20^{2}

a^{2} +256 = 400

a^{2} = 144

a=144

If It's not the hypotenuse:

16^{2}+ 20^{2} =c^{2}

256+400 =c^{2}

656=c^{2}

c = 25.61249695

But I find it unlikely that 20 wasn't the hypotenuse so ignore that unless it applies.

Hope this helped. :0)

5 0
3 years ago
A die-cast plane toy is scaled at 3/16 inch to 1 foot. If the toy is 6.5 inches wide and 8.5 inches long, determine the dimensio
kodGreya [7K]
Given that the die-cast has been represented by 3/16 in to 1 foot, We are are required to calculate for the actual measure of a toy measuring 6.5 inches wide and 8.5 inches long;
the actual width will be given by:
(6.5÷3/16)×1
=34.66666667
=35 feet
The actual length will be given by:
(8.5÷3/16)×1
=45.333
=45 feet
4 0
3 years ago
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