3x+3=3y ⇒ 3y-3x=3 ⇒3(y-x)=3 ⇒ y-x=1
2x-6y=2 ⇒ 2(x-3y)=2 ⇒ x-3y=1
We must to collect two equations.
x's is lost;
y-3y=2
-2y=2
y=-1 ; x-3.(-1)=1 ⇒ x=-2
Answer is (-2,-1)
Answer:
49 - x^2
Step-by-step explanation:
(7+x)(7-x)
We know this is the difference of squares
(a-b) (a+b) = a^2 - b^2
7^2 - x^2 = 49-x^2
We can also FOIL
first = 7*7 = 49
Outer: = 7x
Inner: = -7x
Last : -x*x = -x^2
Add them together
49 +7x-7x - x^2
Combine like terms
49-x^2
The third option is the correct one
Answer:
yes, ±2
Step-by-step explanation:
The x-intercepts are found by setting y=0 and solving for x:
x^2/4 = 1
x^2 = 4
x = ±√4
x = ±2
The x-values of interest are -2 and +2.
DB+ DC= 32
AC+ AC =24
32+24
56