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dimaraw [331]
3 years ago
11

I need help again, as quickly as possible.

Mathematics
1 answer:
mestny [16]3 years ago
5 0

Answer:

{ \tt{ \frac{1}{x}  +  \frac{1}{3}  <  \frac{1}{5} }} \\  \\ { \tt{ \frac{1}{x}   >   -  \frac{2}{15} }} \\  \\ { \tt{x >   - \frac{15}{2} }} \\  \\ { \bf{ -  \frac{15}{2} < x < 0 }}

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The intake pipe can fill a certain tank in 6 hours when the outlet pipe is closed, but when the outlet pipe is open it takes 9 h
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Answer:

18 hours

Step-by-step explanation:

The unit rate of intake pipe is \frac{1}{6}  [1 tank in 6 hours]

The total unit rate (combined) when 2 work together is \frac{1}{9}  [1 tank in 9 hours]

Intake fills up and outlet empties. Thus we can say:

Rate of Intake - Rate of Outlet = Combined Rate

This becomes:

\frac{1}{6}-x=\frac{1}{9}

Where x is the rate of outlet pipe [what we are looking for]

Doing algebra we solve for x:

\frac{1}{6}-x=\frac{1}{9}\\\frac{1}{6}-\frac{1}{9}=x\\x=\frac{9-6}{54}\\x=\frac{3}{54}

This means "outlet pipe can empty 3 tanks in 54 hours". So that would mean 54/3 = 18 hours to empty 1 tank

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4 years ago
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Answer:

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Step-by-step explanation:

6 0
3 years ago
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Answer:

Step-by-step explanation:

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3 0
3 years ago
I ish confuzzled plz help
Lostsunrise [7]

Answer:

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7 0
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