Answer:
The answer is below
Step-by-step explanation:
We need to prove that:
(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.
Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.
Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A
Answer:
5.73
Best of luck
Step-by-step explanation:
So, let's solve all of them and see:
a - (-b) = a + b ⇒ can be either positive or negative, depending on the numbers
a + (-b) = a - b ⇒ can either be positive or negative, depending on the numbers
a * (-b) = a * (-b) ⇒ negative answer no matter what
a / (-b) = a / (-b) ⇒ negative answer no matter what
So the answer is:
<em>"None of the above"</em>.
Hope it helped,
BioTeacher101
(If you have any questions, feel free to ask them in the comments)
Answer:
a¹⁰
Step-by-step explanation:
So here we have (a⁵)², meaning we need to multiply the exponents to get a¹⁰
C. Savings account B because it has more compounding periods per year.
Step-by-step explanation:
Step 1:
Savings account A has an APR of 5% which compounds interest semiannually. This means that savings account A compounds twice in a year. If account A compounds 5% a time, it would compound 5(2) = 10% in a single year.
Step 2:
Savings account B also has an APR of 5% which compounds interest quarterly. This means that savings account B compounds four times in a year. If account B compounds 5% a time, it would compound 5(4) = 20% in a single year.
Step 3:
Savings account A gets an interest of 5% a year while savings account B gets an interest of 10% so account B offers a higher APR because of more compoundings in a year.
