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uysha [10]
3 years ago
11

*Please Help* (Guaranteed brainliest for correct answer!)

Mathematics
2 answers:
Readme [11.4K]3 years ago
5 0
A: 1st one B: 2nd one
FinnZ [79.3K]3 years ago
3 0
Lets say that Williams current age is x, since it is currently unknown
From here we know that in 15 years (x+15) he will be 3 times his age 5 years prior (3x-5). Thus we can set these equations up as equal to one another
1) x + 15 = 3(x - 5)
2) x + 15 = 3x-15
3) 30= 2x
4) 15 = x
5) Now this age is his current age of 15 years, but they also want his age 15 years from now
The equation is x + 15 = 3(x - 5)

This should be correct now, sorry for the misconception. Good luck
 
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What is 2 and 5/6 divided by 6 and 4/5
9966 [12]
Firstly I would revert these back to improper fractions:

So 17/6 ÷ 24/5

Then I would use keep, change, flip

So 17/6 * 5/24

Finally simplify

85/144

Final Answer: 85/144
3 0
3 years ago
Which equation represents the line that passes through the points (-3, 7) and (9, -1)
Law Incorporation [45]

Answer:

y=1/4x+6 1/4

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which intervals show f(x) increasing? choose two options
vivado [14]

Answer:

(-1.6, 0)

(0, 0.8)

Step-by-step explanation:

8 0
3 years ago
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With full explanation from the internet like before<br> 3x2-6x+5=0
Elodia [21]

Answer:

\sf x=1+i\sqrt{\dfrac{2}{3}}   \ \quad and  \quad \:x=1-i\sqrt{\dfrac{2}{3}}

Explanation:

<u>Given Expression</u>:

  • 3x² - 6x + 5 = 0

Use the Quadratic Formula:

\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}  \  \ when   \ \  ax^2 + bx + c = 0

<u>insert coefficients</u>

\Longrightarrow \sf x = \dfrac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}

\Longrightarrow \sf x = \dfrac{\left6\right\pm \sqrt{-24} }{6}

\Longrightarrow \sf x = \dfrac{\left6\right\pm 2\sqrt{6}i}{6}

\Longrightarrow \sf x =1 \pm   i\dfrac{\sqrt{6} }{3}

\Longrightarrow \sf x=1+i\sqrt{\dfrac{2}{3}},  \quad 1-i\sqrt{\dfrac{2}{3}}

6 0
2 years ago
Read 2 more answers
I cant believe how bad my brother, Reuben, is at growing things. He bought a whole bunch of plants at the nursery the other day.
jeka94

Answer:

68 plants.

Step-by-step explanation:

Let x represent the number of plants that Reuben bought from the nursery.

We have been given that Reuben bought a whole bunch of plants at the nursery the other day. Right away, five died. So number of plant left would be x-5.

We are also told that then our dog dug up 2/9 of them. So number of plants left after dug-up would be \frac{2}{9}(x-5).

Further a rabbit came and ate ½ of what was left. So number of plants left would be \frac{\frac{2}{9}(x-5)}{2}=\frac{2}{9\times 2}(x-5)=\frac{1}{9}(x-5).

Since Reuben had only 7 plants left, so we will equate our expression with 7 and solve for x as:

\frac{1}{9}(x-5)=7

9\times \frac{1}{9}(x-5)=7\times 9

x-5=63

x-5+5=63+5

x=68

Therefore, Reuben bought 68 plants at the nursery.

6 0
3 years ago
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