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vichka [17]
3 years ago
12

Connie has 40 apples and 32 oranges.She wants to put all the friuts into several baskets with each typeof fruit has equal number

in all baskets.Every basket must contain apples and oranges.What is the maximum of number of baskets of fruits can she obtain?​
Mathematics
1 answer:
Charra [1.4K]3 years ago
8 0

Answer:

The answer is 9

Step-by-step explanation:

8 x 5 = 40

8 x 4 = 32

5+4= 9

You're welcome hope this helps and have a great day :)

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sergey [27]

Answer: Walk through writing a general formula for the midpoint between two points. ... I believe you would simply find the differences in x and y from the midpoint to the one ... How would you solve a problem in which you do not know point B but are given ... the line y=x and the curve y=4x-x^2 intersect at the point p and q.

Step-by-step explanation:

7 0
3 years ago
In the following equation, when x=3, what is the value of y? -4x + 3y = 12
deff fn [24]

Answer:

y = 8

Step-by-step explanation:

-4(3) = -12

to get -12 to 12 you need to add 24 to -12 to make it 12.

so 3 (8) = 24

so -12 + 24 =12

4 0
3 years ago
Read 2 more answers
The longer base of a trapezoid is 8 ft. The longer base of a similar trapezoid is 13 ft. The area of the smaller trapezoid is 24
Licemer1 [7]

Answer:

390 ft²

Step-by-step explanation:

The longer base of a trapezoid is 8 ft. The longer base of a similar trapezoid is 13 ft. The area of the smaller trapezoid is 240 ft² What is the area of the larger trapezoid?

We solve the above question using proportion

(Longer base/Area of trapezoid) smaller trapezoid = (Longer base/Area of trapezoid) bigger trapezoid

Let the the Area of the bigger trapezoid = x

Hence,

= 8ft/240ft = 13ft/x ft

Cross Multiply

8ft × x = 240ft × 13ft

x = 240ft² × 12 ft/8 ft

x = 390 ft²

3 0
2 years ago
Can anyone please help me with this? i need a step by step explanation please! very appreciated:)
EastWind [94]

Answer:

Step-by-step explanation:

x and y are variables. That means they represent numbers that are unknown. When we solve for x or y, we are trying to find what number the variable represents.

Y is a number that equals both 5x-9 and 3x+7. If it is a number, it can only have one value, so we can say that 5x-9 and 3x+7 have the same value.

In other words, 5x-9 = 3x+7.

Another way of thinking about this step is substitution. y=3x+7, so in the equation y=5x-9, we can replace the y with 3x+7. It will give 3x+7 = 5x-9.

In either case, we have this new equation

5x-9 = 3x+7.

From here it's just simple algebra- subtract 3x from each side

2x -9 = 7

and add 9 to each side

2x = 16

and divide each side by 2.

x = 8.

All these steps work because if two things equal each other, when you do the same thing to both of them (such as add 9), the new values will still equal each other.

Now that we know that x = 8, we can take one of the original equations

y=5x-9

and put 8 in for x.

y=5*(8) -9.

If x represents the value 8, we can obviously switch out x for 8.

Now simplify

y=40 -9

y = 31

Now we know that x = 8 and y = 31.

5 0
2 years ago
Read 2 more answers
A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th
Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let S(t) be the amount of sugar in the tank at time t. Then S(0)=25.

Sugar is added to the tank at a rate of <em>P</em> lb/min, and removed at a rate of

\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}

Separate variables, integrate, and solve for <em>S</em>.

\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt

\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt

-100\ln\left|P-\dfrac S{100}\right|=t+C

\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t

P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}

\dfrac S{100}=P-Ce^{-100t}

S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}

Use the initial value to solve for <em>C</em> :

S(0)=25\implies 25=100P-C\implies C=100P-25

\implies S(t)=100P-(100P-25)e^{-100t}

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick <em>P</em> such that

S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}

5 0
3 years ago
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