The product of two even numbers is even.
Let m and n be any integers so that 2m and 2k are two even numbers.
The product is 2m(2k) = 2(2mk), which is even.
Things to think about:
Why didn’t I just show you by using any two even numbers like the number 4 and the number 26?
Why did I change from "m" to "k" ? Are they really different numbers or could they be the same?
Why did I specifically say that m and k were integers?
The product of two odd numbers is an odd number.
Let m and k be any integers. This means that 2m+1 and 2k+1 are odd numbers.
The product is 4mk + 2m + 2k + 1 (hint: I used FOIL) which can be written as
2 ( 2mk + m + k ) + 1 which is an odd number.
Answer:
A, D
Step-by-step explanation:
Put x = 6 in equations and resultant is 12.
To find the average weight, you need to add all of the numbers and then divide them
I'll start off by doing this:
1/8+1/8 = 2/8
1/4+1/4+1/4+1/4 = 1
3/8+3/8 = 6/8
1/2+1/2 = 1
then I'll add them together:
2/8+6/8 = 1
1 + 1 + 1 =3
now we need to divide the amount of numbers. the amount of sandwiches weighted (10) will have to be divided
therefore, we get 3/10. because this can't be simplified, this will be your final answer.
Answer:
2/3( x^2 + 5 ) = 14 or 2/3x^2 - 32/3
Step-by-step explanation:
Part 1:
Two-thirds ( 2/3 )
of the ( (---) )
sum ( + )
of a number squared ( x^2 ) and 5 ( + 5 )
is fourteen ( = 14 )
Part 2 (Not super confident about):
2/3( x^2 + 5 ) = 14
2/3x^2 + 10/3 = 14
2/3x^2 - 32/3
Hopefully this helps!
Brainliest please?
