Answer:
Rider 1 does one round in 15 min, and will complete another in each consecutive multiple of 15 min
Rider 2 does one round in 18 min, and will complete another in each consecutive multiple of 18 min
Assuming that they start together, they will complete another round together in a time that is both multiples of 15min and 18 min.
Then we need to find the smallest common multiple between 15 and 18.
To smallest common multiple between two numbers, a and b, is equal to:
a*b/(greatest common factor between a and b).
Now, the greatest common factor between 15 and 18 can be found if we write those numbers as a product of prime numbers, such as:
15 = 3*5
18 = 2*3*3
The greatest common factor is 3.
Then the smallest common multiple will be:
(15*18)/3 = 90
This means that after 90 mins, they will meet again at the starting place.
The shapes are similar.
When two figures are similar, the ratios of the lengths of their corresponding sides are equal.
Therefore,
![\frac{42}{(15 + 42)} = \frac{x}{10 + x}](https://tex.z-dn.net/?f=%20%5Cfrac%7B42%7D%7B%2815%20%2B%2042%29%7D%20%3D%20%5Cfrac%7Bx%7D%7B10%20%2B%20x%7D%20)
Simplify:
![\frac{42}{57} = \frac{x}{10 + x}](https://tex.z-dn.net/?f=%20%5Cfrac%7B42%7D%7B57%7D%20%3D%20%5Cfrac%7Bx%7D%7B10%20%2B%20x%7D%20)
Cross multiply:
42(10+x) = 57x
420 + 42x = 57x
420 = 57x - 42x
420 = 15x
x = (420÷15)
x = 28
Your translation is "to solve or decide" hope this helps!
Answer:
1. B
2. B and C
3.C
4.B the answer is 238 but i guess the rounded
Step-by-step explanation: