Answer:
The seed as a fraction of the speed of light is
Solution:
As per the question:
Suppose, be the rate of an identical clock between two time intervals.
For a moving clock, moving with velocity 'v', at the clock tick of four-fifth:
t =
Now,
Using the relation of time dilation, from Einstein's relation:
Squaring both sides:
Answer:
a) r eq = -a/(2b)
b) k = a/r eq = -2b
Explanation:
since
U(r) = ar + br²
a) the equilibrium position dU/dr = 0
U(r) = a + 2br = 0 → r eq= -a/2b
b) the Taylor expansion around the equilibrium position is
U(r) = U(r eq) + ∑ Un(r eq) (r- r eq)^n / n!
,where Un(a) is the nth derivative of U respect with r , evaluated in a
Since the 3rd and higher order derivatives are =0 , we can expand until the second derivative
U(r) = U(r eq) + dU/dr(r eq) (r- r eq) + d²U/dr²(r eq) (r- r eq)² /2
since dU/dr(r eq)=0
U(r) = U(r eq) + d²U/dr²(r eq) (r- r eq)² /2
comparing with an energy balance of a spring around its equilibrium position
U(r) - U(r eq) = 1/2 k (r-r eq)² → U(r) = U(r eq) + 1/2 k (r-r eq)²
therefore we can conclude
k = d²U/dr²(r eq) = -2b , and since r eq = -a/2b → -2b=a/r eq
thus
k= a/r eq
Elephant D does because it is at the highest height and can exert a greater amount of force leading to a greater amount of energy
Answer:
The ball will be overtake superman after travelled distance 248.5 m.
Explanation:
Given that,
Speed of superman = 35 m/s
Height = 330 m
Mass of ball = 10 kg
Let the height at which they are at same position be S.
For superman,
We need to calculate the time
Using equation of motion
...(I)
For ball,
From equation (I) and (II)
Put the value into the formula
We need to calculate the distance travelled
Using formula of distance
Put the value into the formula
Hence, The ball will be overtake superman after travelled distance 248.5 m.
The process is denitrification