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inessss [21]
2 years ago
11

J.J. Thomson discovered the electron by noticing that: A. molecules with the same atoms exhibited the same chemical properties.

B. a beam of particles could be influenced by an electric or magnetic force. C. chemical compounds contained various combinations of at least two atoms. D. some particles in a beam were deflected when passed through a sheet of gold foil.​

Physics
1 answer:
GenaCL600 [577]2 years ago
4 0

J.J. Thomson discovered the electron by noticing that a beam of particles could be influenced by an electric or magnetic force.. That is option B.

<h3>What is an electron?</h3>

An electron can be defined as the part of an atom that is negatively charged and is found revolving round the nucleus of an atom.

J.J. Thomson was the scientist that discovered electrons through subjecting two oppositely-charged electric plates around the cathode ray.

He noticed that the particles where deflected by both the magnetic and electric fields.

Learn more about cathode rays here:

brainly.com/question/4441361

#SPJ1

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PHYSICS QUESTION<br> please answer!! i’ll choose the brainliest
Licemer1 [7]

Explanation:

answer is in the photo attached

6 0
3 years ago
A 2,000 kg car starts from rest and coasts down from the top of a 5.00 m long driveway that is sloped at an angel of 20o with th
ehidna [41]

Answer:

The speed at the bottom of the driveway is3.67m/s.

Explanation:

Height,h= 5sin20°= 1.71m

Potential energy PE=mgh= 2000×9.8×1.71

PE= 33516J

KE= PE- Fk ×d

0.5mv^2= 33516 - (4000×5)

0.5×2000v^2= 33516 - 20000

1000v^2= 13516

v^2= 13516/1000

v =sqrt 13.516

v =3.67m/s

5 0
3 years ago
Is stored energy<br><br> kinetic energy <br> potential energy <br> both
Murrr4er [49]
Potential energy is stored energy while kinetic is energy in motion. So the answer is potential energy.
6 0
4 years ago
Point charges q1 and q2 are separated by a distance of 60 cm along a horizontal axis. The magnitude of q1 is 3 times the magnitu
Alex777 [14]

d = distance between the two point charges = 60 cm = 0.60 m

r = distance of the location of point "a" where the electric field is zero from charge q_{1} between the two charges.

q_{1} = magnitude of charge on one charge

q_{2} = magnitude of charge on other charge

q_{1} = 3 q_{2}

E_{1} = Electric field by charge q_{1} at point "a"

E_{2} = Electric field by charge q_{2} at point "a"


Electric field by charge q_{1} at point "a" is given as

E_{1} = kq_{1} /r²

Electric field by charge q_{2} at point "a" is given as

E_{2} = kq_{2} /(d-r)²

For the electric field to be zero at point "a"

E_{2} = E_{1}

kq_{2} /(d-r)² = kq_{1} /r²

q_{2} /(d-r)² = 3q_{2} /r²

1/(0.60 - r)² = 3 /r²

r = 0.38 m

r = 38 cm


8 0
3 years ago
a Stone is dropped into a deep well and is heard to hit the water 3.41s after being dropped. determine the depth of the well
tangare [24]
Using SUVAT

U = 0 m/s
A = g = 9.8 ms^-2
T = 3.41 s
S = ?

s = ut + 1/2at^2
s = (0)(3.41) + 1/2(9.8)(3.41^)
s = 1/2(9.8)(3.41^2)
s = 1/2(9.8)(11.6281)
s = 56.97769 m
5 0
3 years ago
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