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Iteru [2.4K]
3 years ago
15

Newton’s second law of motion states that when a force acts on an object, the object’s acceleration is equal to _____.

Physics
1 answer:
MatroZZZ [7]3 years ago
3 0

Newton’s second law of motion states that when a force acts on an object, the object’s acceleration is equal to the net force divided by the object’s mass, and is in the same direction as the net force.

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In a World Cup soccer match, Juan is running due north toward the goal with a speed of 7.60 m/s relative to the ground. A teamma
spayn [35]

Answer:

Part a)

v_{bj} = 11.03 m/s

Part b)

\theta = 4.57 degree East of South

Explanation:

Part a)

Velocity of Juan is given as

v_1 = 7.60 m/s \hat j

velocity of the ball is given as

v_2 = 12.9(cos31.4 \hat i + sin31.4\hat j)

now we have

v_2 = 11\hat i + 6.72\hat j

Part a)

We need to find velocity of ball with respect to Juan

so it is given as

v_{bJ} = \vec v_b - \vec v_j

v_{bj} = 11\hat i + 6.72 \hat j - 7.6\hat j

v_{bj} = 11\hat i - 0.88\hat j

magnitude of the speed is given as

v_{bj} = \sqrt{11^2 + 0.88^2}

v_{bj} = 11.03 m/s

Part b)

direction of velocity of the ball

tan\theta = \frac{v_y}{v_x}

tan\theta = \frac{-0.88}{11}

\theta = 4.57 degree East of South

3 0
2 years ago
When you ride a bicycle, in what direction is the angular velocity of the wheels? When you ride a bicycle, in what direction is
Hitman42 [59]

Complete question is;

When you ride a bicycle, in what direction is the angular velocity of the wheels? A) to your left B) to your right C) forwards D) backwards

Answer:

Option A - to your left

Explanation:

While an object rotates, each particle will have a different velocity:

the 'Speed' component will vary with radius while the 'Direction' component will vary with angle.

All of the velocity vectors are aligned in the same plane.

We can be solve this by choosing a single vector normal to ALL of the possible velocity vectors of the rotating object in that plane.

This convention used is known as "Right-hand rule". The angular velocity vector points along the wheel's axle. For instance, if you Imagine wrapping your right hand around the axle so that your fingers point in the direction of rotation, with your thumb sticking out. You will notice that your thumb points to the left.

Thus;

By right-hand rule, a wheel rotating on a forward - moving bicycle has an angular velocity vector pointing to the rider's left.

So, option A is the correct answer

3 0
3 years ago
A 2-kilogram object falls 3 meters. a. How much potential energy did the object have before it fell? b. How much work was accomp
stiks02 [169]
Below are the answers:

(a) Ep = mass x gravitational acceleration x height 
<span>= 2kg x 9.8ms-2 x 3m </span>
<span>= 58.8J </span>

<span>(b) F = mg </span>
<span>= 2kg x 9.8ms-2 </span>
<span>= 19.6N </span>
<span>W = Fd </span>
<span>= 19.6N x 3m </span>
<span>= 58.8J 
</span>
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
6 0
3 years ago
How do I do these? My teacher didn’t show us how.
melisa1 [442]

Explanation:

Displacement is simply the change in position.  So in the first part of problem 1, looking at the graph between 0 s and 2 s, the position changes from 0 m to -4 m.  So the displacement is:

Δx =  -4 m − 0 m

Δx = -4 m

Between 2 s and 4 s, the position stays at -4 m.  The displacement is:

Δx = -4 m − (-4 m)

Δx = 0 m

Finally, between 4 s and 6 s, the position goes from -4 m to 6 m.  The displacement is:

Δx = 6 m − (-4 m)

Δx = 10 m

The net displacement is the change in position from 0 s to 6 s:

Δx = 6 m − 0 m

Δx = 6 m

In the second part of problem 1, we have a velocity vs time graph.

Car 1 starts with 0 velocity and ends with a velocity of 6 m/s, so it is accelerating and constantly moving to the right.

Car 2 starts with a velocity of -6 m/s and ends with a velocity of 6 m/s.  It is also accelerating, but first it is moving to the left, comes to a stop at t = 3 s, then moves to the right.

Car 3 starts with a velocity of 2 m/s and ends with a velocity of 2 m/s.  So it is moving constantly to the right, but never speeds up or slows down.

We want to know when two of the cars meet.  Unfortunately, this isn't as easy as looking for where the lines cross on the graph.  We need to calculate their displacements.  We can do this by finding the area under the graph (assuming all the cars start from the same point).

Let's start with Car 2.  Half of the area is below the x-axis, and half is above.  Without doing calculations, we can say the total displacement for this car is 0.  This means it ends back up where it started, and that it never meets either of the other cars, both of which have positive displacements.

So we know Car 1 and Car 3 meet, we just have to find where and when.  For Car 1, the area under the curve is a triangle.  So its displacement is:

Δx = ½ t v(t)

where t is the time and v(t) is the velocity of Car 1 at that time.  Since the line has a slope of 1 and y intercept of 0, we know v(t) = t.  So:

Δx = ½ t²

Now look at Car 3.  The area under the curve is a rectangle.  So its displacement is:

Δx = 2t

When the two cars have the same displacement:

½ t² = 2t

t² = 4t

t² − 4t = 0

t (t − 4) = 0

t = 0, 4

t = 0 refers to the time when both cars are at the starting point, so t = 4 is the answer we're looking for.  Where are the cars at this time?  Simply plug in t = 4 into either of the equations we found:

Δx = 8

So Cars 1 and 3 meet at 4 s and 8 m.

7 0
2 years ago
An experiment that produces waves on a string is analyzed, and the experimental value for the wave speed is found to be 66 m/s.
Alexandra [31]

4.8 is the correct answer

7 0
3 years ago
Read 2 more answers
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