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3 years ago

Newton’s second law of motion states that when a force acts on an object, the object’s acceleration is equal to _____.

1 answer:

3 0

Newton’s second law of motion states that when a force acts on an object, the object’s acceleration is equal to the net force divided by the object’s mass, and is in the same direction as the net force.

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seropon [69]

The slowest line is the solid line and the fastest is the dotted line that crosses the solid line
for future reference you just need to find the slope or the line which is traveling most vertical

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2 years ago

This diagram of the first right-hand rule relates which two quantities?

AURORKA [14]

Option A, current (thumb) to magnetic field (fingers)

As per the First right-hand rule,

Using right hand, if we suppose that thumb points towards the electric current

fingers curl towards the magnetic field

7 0

3 years ago

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If an X-ray beam of wavelength 1.4 × 10-10 m makes an angle of 20° with a set of planes in a crystal causing first order constru

Flura [38]

Answer:

43.16°

Explanation:

λ = Wavelength = 1.4×10⁻¹⁰ m

θ₁ = 20°

n can be any integer

d = distance between the two slits

Since for the first bright fringe, n₁ = 1

n₂ = 2 for second order line

The relation between the distance of the slits and the angle through which it is passed is:

dsinθ=nλ

As d and λ are constant

$\frac{n_1\lambda}{sin \theta_1}=\frac{n_2\lambda}{sin \theta_2}\\\Rightarrow \frac{1}{sin20}=\frac{2}{sin\theta_2}\\\Rightarrow sin\theta_2=\frac{2}{\frac{1}{sin20}}\\\Rightarrow \theta_2=sin^{-1}{\frac{2}{\frac{1}{sin20}}}\\\Rightarrow \theta_2=43.16^{\circ}$

∴ Angle by which the second order line appear is 43.16°

5 0

2 years ago

The energy from 0.015 moles of octane was used to heat 250 grams of water. The temperature of the water rose from 293.0 K to 371

arsen [322]

Answer : The correct option is, (B) -5448 kJ/mol

Explanation :

First we have to calculate the heat required by water.

$q=m\times c\times (T_2-T_1)$

where,

q = heat required by water = ?

m = mass of water = 250 g

c = specific heat capacity of water = $4.18J/g.K$

$T_1$ = initial temperature of water = 293.0 K

$T_2$ = final temperature of water = 371.2 K

Now put all the given values in the above formula, we get:

$q=250g\times 4.18J/g.K\times (371.2-293.0)K$

$q=81719J$

Now we have to calculate the enthalpy of combustion of octane.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of combustion of octane = ?

q = heat released = -81719 J

n = moles of octane = 0.015 moles

Now put all the given values in the above formula, we get:

$\Delta H=\frac{-81719J}{0.015mole}$

$\Delta H=-5447933.333J/mol=-5447.9kJ/mol\approx -5448kJ/mol$

Therefore, the enthalpy of combustion of octane is -5448 kJ/mol.

5 0

3 years ago

Match each phrase to the form of energy it represents. Tiles chemical potential energy electric energy vibrational energy motion

alex41 [277]

fuel in a car's gas tank- Chemical Potential Energyflash of lightning- Radiant Energy storm clouds- Electric Energyvocalist singing- Vibrational Energy recording sound with a microphone- Electric Potential Energyraindrops falling- Motion Energy
HOPE THIS HELPED :)

5 0

3 years ago

Read 2 more answers