All categories

3 years ago

Newton’s second law of motion states that when a force acts on an object, the object’s acceleration is equal to _____.

1 answer:

3 0

Newton’s second law of motion states that when a force acts on an object, the object’s acceleration is equal to the net force divided by the object’s mass, and is in the same direction as the net force.

You might be interested in

I don’t know if I did these rights someone check them or give me the answers? I know the photo has some stuff cut off but you ca

Nana76 [90]

I can’t read some of your work

3 0

3 years ago

1. An object 20 cm away from a lens produces a focused image on a film 15 cm away, what is the focal length

morpeh [17]

8.6 cm

Explanation:

Step 1:

In this we have to find the focal length of converging lens.

To find focal length we have,

$(1/u) + (1/v) = (1/f)$

where u = Object distance

v= Image distance

f = Focal length

Step 2:

$(1/f) = (1/20) + (1/15)$

(1/f) = 0.116

f = 1/0.116

f = 8.6 cm

6 0

3 years ago

The power of a red laser (λ = 630 nm) is 3.25 watts (abbreviated w, where 1 w = 1 j/s). how many photons per second does the las

lisabon 2012 [21]

The energy delivered by the laser in 1 second is $E_t=Pt = (3.25 W)(1.0 s)=3.25 J$
In order to find how many photons correspond to this energy, we must calculate the energy of a single photon.
Calling h the Planck constant, c the speed of light and $\lambda=630 nm=630 \cdot 10^{-9}m$ the wavelength of the light, the energy of a single photon is given by
$E=h \frac{c}{\lambda}=(6.6 \cdot 10^{-34} Js) \frac{3 \cdot 10^8 m/s}{630 \cdot 10^{-9}m}= 3.1 \cdot 10^{-19} J$

So, the number of photons emitted by the laser in 1 second is equal to the total energy delivered by the laser divided by the energy of a single photon:
$N= \frac{E_t}{E}= \frac{3.25 J}{3.1 \cdot 10^{-19} J} =1.0 \cdot 10^{19}$ photons

5 0

3 years ago

What shape is the Milky way galaxy

gizmo_the_mogwai [7]

It appears to be a <span>spiral shape. </span>

5 0

3 years ago

Read 2 more answers

Light with an intensity of 1 kW/m2 falls normally on a surface with an area of 1 cm2 and is completely absorbed. The force of th

kogti [31]

Answer:

The force of the radiation on the surface is 3.33 x 10⁻¹⁰ N

Explanation:

Given;

intensity of light, I = 1kw/m² = 1000 W/m²

area of the surface, A = 1 cm² = 1 x 10⁻⁴ m²

Since the light is completely absorbed, the force of the radiation is given by;

F = P/c

where;

c is the speed of light = 3 x 10⁸ m/s

But P = IA

F = IA /c

F = (1000 X 1 X 10⁻⁴) / 3 x 10⁸

F = 3.33 x 10⁻¹⁰ N

Therefore, the force of the radiation on the surface is 3.33 x 10⁻¹⁰ N

4 0

4 years ago