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Novosadov [1.4K]
3 years ago
8

Two people timed an object with a stop watch .They each got a slightly different result. How could this be ?

Physics
1 answer:
Maurinko [17]3 years ago
6 0

One of the key differences between franchising and chain stores is the amount of risk involved. When a company chooses to expand with chain stores, it assumes all of the risk on its own. It funds the entire expansion project. By comparison, when a company franchises, it passes some of the risk onto other investors. Franchising represents less risk for the parent company, but it shifts the risk to the franchisee.

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Predict the gravitational force between two 15-kg balls whose centers are 35 m apart.
ArbitrLikvidat [17]

F=G\frac{m_1-m_2}{r^2}

=\frac{(6.67\times10^{-11}N*m/kg^2)(15kg) }{(0.35m)^2}

=1.2\times10^{-7} N

Because the weight of one ball is mg = 147 N, the gravitational force between the two balls is 1.2\times10^{-7}N or 8.4*10^3 parts per billion of the  weight.

5 0
2 years ago
How will the world end?
Law Incorporation [45]

Answer:

no one knows

Explanation:

7 0
3 years ago
A penny is dropped from the top of a building 290 m high. Ignoring air resistance, if
mel-nik [20]

Answer:

Vf = 75.4 m/s

Explanation:

In order to find the final velocity of the penny when it would hit the ground, we will use the equation of motion. In this particular case the third equation of motion can be used. The third equation of motion is written as follows:

2gh = Vf² - Vi²

where,

Vf = Final Velocity of the penny when it would hit the ground = ?

Vi = Initial Velocity of the penny = 0 m/s (Since, the penny starts from rest)

g = acceleration due to gravity = 9.8 m/s²

h = height of building = 290 m

Therefore,

2(9.8 m/s²)(290 m) = Vf² - (0 m/s)²

Vf = √(5684 m²/s²)

<u>Vf = 75.4 m/s</u>

3 0
3 years ago
A car moves along an x axis through a distance of 900 m, starting at rest (at x = 0) and ending at
OlgaM077 [116]
A car moves along an x axis through a distance of 900 m, starting at rest (at x = 0) and ending at rest (at x = 900 m). Through the first 1/4 of that distance, its acceleration is +6.25 m/s2. Through the next 3/4 of that distance, its acceleration is -2.08 m/s2. What are (a) its travel time through the 900 m and (b) its maximum speed? 

<span>Solve for the time at the 1/4 mark. That's 225 m. How? d = (1/2)at^2 ( initial velocity zero). Thus 225 = (1/2) 6.25 t^2. t^2 = ( 225 * 2 ) / 6.25. t = 8.5 sec. </span>

<span>At the other end t^2 = (675 * 2) / 2.08 -- we reversed the sign and ran time backwards. t = 25.5 sec. </span>

<span>So total time is 8.5 + 25.5 or 34 sec. </span>

<span>Since zero initial velocity: v^2 = 2 a d. Here, v^2 = 2 * 6.25 * 225. v = 53 m/s. That's the fastest speed since braking then occurs.</span>
7 0
4 years ago
While looking at bacteria under a microscope you decide to take a break when u return the amount of bacteria has doubled in size
VikaD [51]
Your break probably only took 20-30 minutes. Bacteria can double every 20-30 minutes. Hope this helped!
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3 years ago
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