C
Rocks are classified on the basis of their formations.
Answer:
The normal stress is 10.7[MPa]
Explanation:
The normal stress can be calculated with the following equation:
![S_{norm} =\frac{F}{A} \\where:\\F= force [Newtons]\\A=area [m^2]\\S_{norm} = Normal stress [\frac{N}{m^{2} }] or [Pa]](https://tex.z-dn.net/?f=S_%7Bnorm%7D%20%3D%5Cfrac%7BF%7D%7BA%7D%20%5C%5Cwhere%3A%5C%5CF%3D%20force%20%5BNewtons%5D%5C%5CA%3Darea%20%5Bm%5E2%5D%5C%5CS_%7Bnorm%7D%20%3D%20Normal%20stress%20%5B%5Cfrac%7BN%7D%7Bm%5E%7B2%7D%20%7D%5D%20or%20%5BPa%5D)
The area of the rod can be calculated using the equation:
![A=\frac{\pi }{4}*d^{2} \\d=8[mm]=0.008[m]\\A=\frac{\pi }{4}*(0.008)^{2} \\A=5.02*10^{-5} [m^{2} ]](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B%5Cpi%20%7D%7B4%7D%2Ad%5E%7B2%7D%20%20%5C%5Cd%3D8%5Bmm%5D%3D0.008%5Bm%5D%5C%5CA%3D%5Cfrac%7B%5Cpi%20%7D%7B4%7D%2A%280.008%29%5E%7B2%7D%20%20%5C%5CA%3D5.02%2A10%5E%7B-5%7D%20%5Bm%5E%7B2%7D%20%5D)
The force is the result of the mass multiplied by the gravity.
![F=55[kg]*9.81[m/s^{2} ] = 539.6[N]\\\\S_{norm} = 539.6/5.02*10^{-5} \\S_{norm} = 10.7*10^{6}[Pa] = 10.7[MPa]](https://tex.z-dn.net/?f=F%3D55%5Bkg%5D%2A9.81%5Bm%2Fs%5E%7B2%7D%20%5D%20%3D%20539.6%5BN%5D%5C%5C%5C%5CS_%7Bnorm%7D%20%3D%20539.6%2F5.02%2A10%5E%7B-5%7D%20%5C%5CS_%7Bnorm%7D%20%3D%2010.7%2A10%5E%7B6%7D%5BPa%5D%20%3D%2010.7%5BMPa%5D)
Answer:
T= 224.01 N
Explanation:
in imminent motion we have to :
- The frictional force reaches its maximum value
- The system is in balance of forces
Data
W= 500 N : weight of the log
μs = 0.5
μk = 0.35
α = 30°above the ground : angle of the cable attached to the log
Newton's first law to the log:
∑F =0 Formula (1)
∑F : algebraic sum of the forces in Newton (N)
Forces acting on the log
T: cable tension for impending movement
N: normal force
W : weight
f: frictional force , f= μsN
We apply the formula (1)
∑Fx=0
Tx-f = 0
Tcosα-μsN=0
Tcos30°-0.5N=0 Equation (1)
∑Fy=0
N+Ty-W=0
N+Tsin30°-500=0
N= 500-Tsin30° Equation (2)
We replace the value of N of the Equation (2) in the equation (1)
Tcos30°-0.5(500-Tsin30°) = 0
Tcos30°+0.5Tsin30° = 0.5*500
T( cos30°+0.5*sin30°) = 250
(1.116) T = 250
T= 250/1.116
T= 224.01 N
Molten Mattet Seeps through the crust and forms new land.
Answer:
60000 newtons
Explanation:
Force=mass × acceleration
60000
