Answer:
x = 0.0537 m or 5.37 cm
Explanation:
Given:
spring constant'k'= 4900 N/m
radius 'r' =0.029 m
Area 'A' =r²π = 0.029²π => 2.6 x m²
Here, Pressure 'P' is given by,
Pressure = Force / Area
And we know that, for a spring :
F = kx, where k is the spring constant and x is the change in length.
P = kx/A
As P = 101325 Pa
101325 = 4900x / ( 2.6 x )
x = 0.0537 m or 5.37 cm
The astronaut will take 300 seconds
Explanation:
We can solve this problem by using the law of conservation of momentum.
In fact, the total momentum of the astronaut+object system must be conserved.
Initially, they are both at rest, so their total momentum is zero:
After the astronaut throws the object, their total momentum is:
where:
M = 80 kg is the mass of the astronaut
V is the final velocity of the astronaut
m = 500 g = 0.5 kg is the mass of the object
v = 8.0 m/s is the velocity of the object
Since momentum is conserved, we can write
And solving for V,
Which means that he starts moving at 0.05 m/s in the direction opposite to the object.
Now the astronaut needs to cover a distance of
d = 15.0 m
And his speed is
v = 0.05 m/s
Therefore, the time taken is
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Answer:
b. 0.20 m/s.
Explanation:
Given;
initial mass, m = 0.2 kg
maximum speed, v = 0.3 m/s
The total energy of the spring at the given maximum speed is calculated as;
K.E = ¹/₂mv²
K.E = 0.5 x 0.2 x 0.3²
K.E = 0.009 J
If the mass is changed to 0.4 kg
¹/₂mv² = K.E
mv² = 2K.E
Therefore, the maximum speed is 0.20 m/s