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3 years ago

Which muscle is the main muscle of mastication?

Physics

1 answer:

Valentin [98]3 years ago

4 0

Answer: Masseter muscle

Explanation:

The masseter muscle is the most powerful muscle of mastication. It is quadrangular in shape and has two parts: deep and superficial. The entirety of the muscle lies superficially to the pterygoids and temporalis, covering them.

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Find a model for simple harmonic motion that has an initial displacement (t=0) of 0 inches, an amplitude of 5 inches, and a freq

Svetach [21]

Answer:

The equation of simple harmonic motion is $y=5\sin{(8\pi t)}$

Explanation:

Given that,

Amplitude = 5 inches

Frequency $f= \dfrac{4}{3}$

As per the question initial displacement is zero at t = 0 for sine curve.

The displacement is zero so the phase difference will be zero.

We know that,

The general equation of simple harmonic motion

$y=A\sin(\omega t+\phi)$

Where, A = amplitude

$\omega$ = angular frequency

$\phi$ = phase shift

We need to calculate the time period

Using formula of frequency

$f=\dfrac{1}{T}$

$T=\dfrac{1}{f}$

Put the value into the formula

$T=\dfrac{1}{\dfrac{4}{3}}$

$T=\dfrac{3}{4}$

We need to calculate the angular frequency

Using formula of angular frequency

$\omega=\dfrac{2\pi}{T}$

$\omega=\dfrac{2\pi\times4}{3}$

Put the value into the general equation

$y=5\sin{(8\pi t)}$

Hence, The equation of simple harmonic motion is $y=5\sin{(8\pi t)}$

7 0

3 years ago

A racecar traveling at a velocity of 18.5 m/s, accelerates at a rate of 2.47 m/s2 and covers a distance of 79.78 m. Determine th

Vesna [10]

Answer:

The final velocity of the race car is 27.14 m/s

Explanation:

Given;

initial velocity of the race car, u = 18.5 m/s

acceleration of the race car, a = 2.47 m/s²

distance covered by the race car, s = 79.78 m

Apply the following kinematic equation to determine the final velocity of the race car.

v² = u² + 2as

v² = (18.5)² + 2(2.47)(79.78)

v² = 736.363

v = √736.363

v = 27.14 m/s

Therefore, the final velocity of the racecar is 27.14 m/s

4 0

3 years ago

an force of 5N is applied to a 10 kg object over a time of 3s. Determine the impulse applied to the object

ddd [48]

Answer:

15Ns

Explanation:

Given parameters:

Mass of the object = 10kg

Force impact = 5N

Time of action = 3s

Unknown:

Impulse applied on the object = ?

Solution:

Impulse is the force that acts on object within a period of time.

Mathematically;

Impulse = Force x time

Now insert the parameters and solve;

Impulse = 5 x 3 = 15Ns

7 0

2 years ago

The amplitude of a pendulum is doubled. This means:

Serjik [45]

Answer:

the period of the pendulum will be twice as long.

Explanation:

because i looked it up

8 0

3 years ago

For the pulley system shown, the rope must be raised 2 meters for every meter the block is raised. What force must be applied to

Dovator [93]

The force applied to raise the block would be 250N

6 0

3 years ago