Answer:
The 95% confidence interval for mean compressive strength is:

Step-by-step explanation:
We have a sample of n=12 specimens, with sample mean=3259.9 and sample standard deviation = 35.57.
We know the population is normally distributed.
For a 95% confidence interval and df=n-1=11, the t-statistic is t=2.201.
Then, the CI can be expressed as:

Answer:
B
Step-by-step explanation:
Answer:
m ∠RMK = 51°
Step-by-step explanation:
m ∠JMK = m ∠RMK + m ∠JMR
10x + 19 = 7x - 26 + 6x + 12
10x +19 = 13x -14
19 = 3x -14
33 = 3x
11 = x
m ∠RMK = 7(11) - 26 = 51°
m ∠JMR = 6 (11) + 12 = 78
Step-by-step explanation:
you add the three p to p and that's 4p and
4p+7-5=-10
4p-2=-10
+2=+2
4p=-8
devide by four on both side so p is-2