Answer:
13 yards
Step-by-step explanation:
Required distance moved from original position should be ≥ 10 yards in other to get a first down.
Run on first play = 6 yards
Second play = - 9yards
The least number of yards needed on third play :
Let yard needed on third play = x
First play + second play + third play = 10
6 + (-9) + x = 10
6 - 9 + x = 10
-3 + x = 10
x = 10 + 3
x = 13 yards
At least 13 yards is needed on third playbto get a first down.
Answer:
x=-59
Step-by-step explanation:
3x+2-4x=61
-x+2=61
-x=59
x=-59
Answer:
Step-by-step explanation:
area= (17x9)-(16x6)
area=153-96
area=57
Answer:
a)
b)
c)
Step-by-step explanation:
The problem states that there is a 97% probability that a parts inspected is classified correctly. So, there is a 3% probability that a part inspected is not classified correctly.
So
(A) x = 0, f(x) = ?
What is the probability that each part is not classified correctly?
There is a 0.0027% probability that no part is classified correctly
(B) x = 1, f(x) = ?
What is the probability that exactly one part is classified correctly?
We have to take into account that it may be the first part classified correctly, the second or the third. So we have to permutate. We have a permutation of 3 parts with 1(classified correctly) and 2(classified incorrectly) repetitions.
So
There is a 0.2619% probability that no part is classified correctly.
(C) x = 2, f(x) = ?
What is the probability that exactly two parts are classified correctly?
We also have the permutation of 3 parts with 2 and 1 repetitions.
So:
There is a 8.4681% probability that exactly two parts are classified correctly.
(D) x = 3, f(x) = ?
There is a 91.2673% probability that every part is classified correctly
Answer:
D: 38
Step-by-step explanation:
48 - 10 = 38