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pshichka [43]
3 years ago
12

I dont really understand this so can someone help me please!

Mathematics
1 answer:
pychu [463]3 years ago
3 0
The area of a circle is pi times the radius squared. the radius of this circle is 16.8cm, which is 282cm when squared. multiplied by pi it becomes 887cm.
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The value of the expression a³-2a²+3a+5 for a = -1
mrs_skeptik [129]

Answer:

- 1

Step-by-step explanation:

Substitute a = - 1 into the expression, that is

(- 1)³ - 2(- 1)² + 3(- 1) + 5

= - 1 - 2(1) - 3 + 5

= - 1 - 2 - 3 + 5

= - 6 + 5

= - 1

4 0
3 years ago
Read 2 more answers
Question60 is 40% of what number?
Natalka [10]

let the required number be x then

\begin{gathered} \frac{60}{x}\times100=40 \\ x=\frac{60}{40}\times100 \\ x=150 \end{gathered}

So 60 is 40% of 150.

7 0
1 year ago
-3/4 plus -8/9
Vinil7 [7]

Answer:

-3/4 -8/9

take LCM

<u>-3*9-8*4</u>

    36

<u>-27 -32</u>

  36

-59/36

Step-by-step explanation:

3 0
2 years ago
Write the vector v in the form aiplusbj​, given its magnitude left norm Bold v right norm and the angle alpha it makes with the
photoshop1234 [79]

Answer:

6\sqrt{3}i-6j

Step-by-step explanation:

Given:

The magnitude, v=12

The angle \alpha it makes with the positive​ x-axis =150^0

Now for a vector (x,y)

  • \alpha =tan^{-1}(\frac{y}{x} ) ; and
  • v=\sqrt{x^2+y^2}

Therefore:

150 =tan^{-1}(\frac{y}{x} )\\\frac{y}{x} =tan 150\\\frac{y}{x}=-\frac{\sqrt{3} }{3}

y=-\frac{x \sqrt{3}}{3}

Similarly:

v=\sqrt{x^2+y^2}\\12=\sqrt{x^2+y^2}\\12^2=x^2+y^2\\144=x^2+y^2

144=x^2+(-\frac{x \sqrt{3}}{3} )^2\\144=x^2+\frac{3x^2}{9} \\144=\frac{4x^2}{3}\\4x^2=144 X 3=432\\x^2=108\\x=6\sqrt{3}

Recall that:

y=-\frac{x \sqrt{3}}{3}\\y=-\frac{6\sqrt{3}  \sqrt{3}}{3}=-6

Therefore: (x,y)=(6\sqrt{3}, -6)

The vector in the form ai+bj is therefore:

6\sqrt{3}i-6j

6 0
3 years ago
A figure was translated 4 units down and 3 to the left then reflected over the y-axis. The figures are
Mumz [18]

Answer:

Congruent and similar

Step-by-step explanation:

because you did not change anything about the shape that shape is still the same size and shape just in a different spot

4 0
2 years ago
Read 2 more answers
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