You need to factor the numerator and denominator...

(2x^2+4x-2x-4)/(2x^2-2x-2x+2)

(2x(x+2)-2(x+2))/(2x(x-1)-2(x-1))

((2x-2)(x+2))/((2x-2)(x-1)) so the (2x-2)s cancel out leaving

(x+2)/(x-1)

4 0

3 years ago

Read 2 more answers

Is this correct ? if not what’s the correct answer?

Snezhnost [94]

Answer:

yes

Step-by-step explanation:

4 0

2 years ago

A baseball is thrown with an upward velocity of 32 feet per second. The equation h=-16t^2+32t gives the height of the ball t sec

AnnZ [28]

Answer:

The function of height has a maximum value.

Step-by-step explanation:

Maximum or Minimum:

A given function f(x).

Find out f'(x) and f''(x)
Then set f'(x)=0 which gives x=a.
f''(a) > 0 , then at x=a , f(x) has minimum value.
If f''(a)<0 , then at x=a, f(x) has maximum value.

Given that, a baseball is thrown with with an velocity of 32 feet per second.

The equation of height is

$h=-16t^2+32t$

Differentiating with respect to t

$h'=-32 t+32$

Again differentiating with respect to t

$h''=-32$

Next, we set h'=0

$-32 t+32=0$

$\Rightarrow 32t=32$

$\Rightarrow t=1$

Now $h''|_{t=1}=-32$

Since at t=1, h''<0.

The function of height has a maximum value.

The maximum of h is = -16.(1)²+32

= -16+32

=16 feet

4 0

3 years ago

Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are 36 and 2304, respectively.

poizon [28]

Answer:

$a_n=9(4^{n-1})$

Step-by-step explanation:

we know that

In a <u>Geometric Sequence</u> each term is found by multiplying the previous term by a constant, called the common ratio (r)

In this problem we have

$a_2=36\\ a_5=2,304$

Remember that

$a_2=a_1(r)$ -----> $36=a_1(r)$ -----> equation A

$a_5=a_4(r)$

$a_5=a_3(r^{2})$

$a_5=a_2(r^{3})$

Substitute the values of a_5 and a_2 and solve for r

$2,304=36(r^{3})$

$r^{3}=2,304/36$

$r^{3}=64$

$r=4$

Find the value of a_1 in equation A

$36=a_1(4)$

$a_1=9$

therefore

The explicit rule for the nth term is

$a_n=a_1(r^{n-1})$

substitute

$a_n=9(4^{n-1})$

3 0

3 years ago