All categories

3 years ago

If the equation of a circle is (x +5)^ + (y-7)^ =36, it’s radius is ?

1 answer:

6 0

If I am guessing the exponent correctly for your equation and it really is :

(x+5)² + (y-7)² = 36

then your answer would be answer choice A(6)

You might be interested in

You rotate triangle ABC, with vertices A(-3, 1), B(-2, 2), and C(-3, 4), 90° counterclockwise about the origin to form triangle

katrin2010 [14]

The rule for going 90 degree counter clockwise is:
(x, y) becomes (y, -x)

Therefore, the new points are:

A(-3, 1) to (1, 3)
B(-2, 2) to (2, 2)
C(-3, 4) to (4, 3)

6 0

3 years ago

Read 2 more answers

What are the vertices of the hyperbola whose equation is (y+6)^2/81 - (x+8)^2/49 = 1

olchik [2.2K]

Answer:

(-8,3) and (-8, -15)

Step-by-step explanation:

3 0

3 years ago

Solve for the variable: 12 = 5x = 7

IrinaVladis [17]

Hello from MrBillDoesMath!

Answer: x = 1

Discussion :

Per the author, the equation to solve is 12 = 5x + 7

Isolate the "x" variable by subtracting 7 from both sides of the equation:

12 = 5x + 7

-7 = -7

---------------------

12-7 = 5x + 0

5 = 5x

Dividing both sides by 5 gives x - 1

Regards, MrB

6 0

3 years ago

A particle p is moving along the x-axis the displacement x metres from O can be writen as x=t^5-12t²+9 find the velocity

Lisa [10]

Answer:

$v = t (5t^{3} - 24)$

Step-by-step explanation:

We are given an expression to solve for the displacement (x), so in order to find velocity (v), we need to differentiate the function.

============================================================

Solving :

⇒ $\frac{dx}{dt} = \frac{d}{dx} (t^{5} - 12t^{2} + 9)$

⇒ $v = (5)t^{5-1} - (2)12t^{2-1} + 0$

⇒ $v = 5t^{4} - 24t$

⇒ $v = t (5t^{3} - 24)$

Using this equation, we can find the velocity if a value of t is given.

5 0

2 years ago

The formula for finding the length of an arc on a circle is L=2πr(x360) , where r is the radius of the circle and x is the measu

horrorfan [7]

The formula for length of an arc on a circle is given by the formula:

$L = \frac{2 \pi rx}{360}$ ,

where 'r' is the radius of the circle and 'x' is the measure of the central angle of the arc.

We have to determine the value of radius 'r'.

Since, $L = \frac{2 \pi rx}{360}$

By Cross multiplication, we get

$360 \times L = 2 \pi rx$

$\frac{360 \times L}{ 2 \pi x} =r$

$\frac{180 \times L}{ \pi x} =r$

$r = \frac{180L}{ \pi x}$

Therefore, the radius 'r' is given by $r = \frac{180L}{ \pi x}$ .

Option 4 is the correct answer.

6 0

3 years ago

Read 2 more answers