& inequally

storchak [24]

Answer:

57.72 in^2

Step-by-step explanation:

Question 1. Shapes are triangle, semi-circle, and rectangle.

Question 2.Find area of rectangle first. Then area of triangle and circle. Subtract area of triangle and circle. Then add the difference with the rectangles area.

Question 3.

Rectangle's area:48 in^2

Triangles area:8*4/2= 16 in^2

Circle Area: pi*r^2/2(since its a semi-circle)

3.14*2^2=3.14*4=12.56/2=6.28 in^2

Question 4.

16-6.28=9.72

9.72+48=57.72 in^2

5 0

2 years ago

There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=

yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = $\frac{12P4}{12^{4} }$

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = $\frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }$

P(X=2) = 0.401

P(X=3) = $\frac{4C3 * 12P2}{12^{4} }$

P(x=3) = 0.025

P(X=4) = $\frac{12}{12^{4} }$

P(X=4) = 0.001

Mean, $\mu = \sum xP(x)$

$\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879$

Standard deviation, $SD = \sqrt{\sum x^{2} P(x) - \mu^{2}} \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2} * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}$

SD = 1.033

4 0

3 years ago

Comparing Standard Deviations

inessss [21]

Explanation:

There may be a couple of reasons for this:

1. Each team represents a sample of the players in the league. The averages of (random) samples can be expected to have a standard deviation that is smaller than the population standard deviation by a factor related to sample size.

2. A team average will result from the players who are played the most. Each team can be expected to field players more often whose averages are among the highest. The standard deviation of a set of the top tier of players will necessarily be smaller than the standard deviation of the set of all players.

8 0

3 years ago

there are 10 million bacteria per square centimeter of coral in a coral reef. the coral reefs near the Hawaiian islands cover 14

Karo-lina-s [1.5K]

4000000000
multiply them

7 0

3 years ago

If rain is falling at 0.5 inches per hour and 1.5 inches have already accumulated, how many hours must have passed if there are

zavuch27 [327]

Given :

Rain is falling at 0.5 inches per hour and 1.5 inches have already accumulated.

To Find :

How many hours must have passed if there are 5 inches of rain .

Solution :

Let , after x hours rain accumulated is 5 inches .

We know , general equation of line :

y = mx +c

Here , m = 0.5 and c = 1 .

So , equation of rain accumulated is :

$y=0.5x+1$

Now , putting value of x = 5 hours .

We get :

$y=0.5\times 5+1\\\\y=2.5+1=3.5\ inches$

Hence , this is the required solution .

7 0

3 years ago