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Vilka [71]
3 years ago
9

80:(8+2)a. 12b. 11c. 1

Mathematics
2 answers:
german3 years ago
6 0
I think something is not right here, the answer supposed to be 8
Levart [38]3 years ago
5 0
Yes! The answer should be 8
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Muhammad, a shipping and receiving clerk, uses 1 yard, 2 feet, 4 inches of twine to wrap each carton he packs. He has to pack 29
Vsevolod [243]

Answer:

 Twine needed to wrap 29 cartons = 51.55 yards

Explanation:

 1 feet = 0.3333 yard

 1 inch = 0.0277778 yard

Twine needed to wrap one carton = 1 yard, 2 feet, 4 inches

                                                           = 1 + 2 x 0.3333 + 4 x 0.027778

                                                           = 1.777712 yards.

 Twine needed to wrap 29 cartons = 1.777712 x 29 = 51.55 yards.

 Twine needed to wrap 29 cartons = 51.55 yards

4 0
3 years ago
What decimal is equivalent to 1.25%
matrenka [14]
The answer is 0.0125
5 0
3 years ago
Read 2 more answers
The cost of buying a small piece of land in a remote village since the year 1990 is represented by the following table . Which m
Effectus [21]

Answer:

C(t)=30+3.5t

Step-by-step explanation:

Yeah this is the answer

5 0
3 years ago
Read 2 more answers
Walk fifty meters at 30o north or east from the old oak tree. (2) Turn 45o to your left (you should now be facing 75o north of e
saw5 [17]

Answer:

A straight line of approximately 75 meters, 1.4º north

Step-by-step explanation:

Hi, let's make it step by step to make it clearer

1) If we walk 50 meters in 30º angle Northeast, assuming the Old Oak tree is the point 0,0 and we're dealing with vectors in R^{2}. To say 30º Northeast is 30º clockwise (or 60º counter clockwise).

2) Then there was a the turning point to the left. If I turn to the left, on my compass 45º , I'll face 75º northeast.

3) Finally, the last vector leads to the treasure from the Old Oak Tree, i.e. the resultant.

So, let's calculate the norm which is the length of the each vector.

1) Graphing them we can find the points, then the components and then calculate the norm, the length of each vector.  

Since the Oak Tree is on (0,0). The turning point (50,86.61) and the Rock (R=(1.4,74,85) we can write the following vectors:

\vec{u}=\left \langle 50,86.61 \right \rangle\\\vec{v}=\left \langle -48.6,-11.76\right \rangle\\\vec{w}=\left \langle 1.4,74.85 \right \rangle

Now, let's calculate each vector length by calculating the norm.

\left \| \vec{u} \right \|=\sqrt{50^{2}+86.6^2}=100\\\left \| \vec{v} \right \|=\sqrt{(-48.6)^2+(-11.76)^2}=50\\\left \| \vec{u} \right \|=\sqrt{(1.4)^2+(74.85)^2}=74.86

The path is almost 75 meters. And since it is less than 15º degrees to the left of the North (or to the right) its direction is still north of the Old Oak Tree.

8 0
3 years ago
Question in attachment​
Damm [24]

Answer:

a) scale factor = 1.5

b) d length is 7.5

c) Area scale factor is 2.25

Step-by-step explanation:

Given QR =6

And ST =9

Length Scalar factor = enlarged length /previous length

 =9/6

 =1.5

Length Scalar factor =1.5

b)we know PS enlarged length of PQ

Length scale factor = PS/PQ

1.5 =PS/5

PS =5×1.5

PS =d =7.5

d length is 7.5

c)Formula :

Area scale factor = (length scale factor)2

=(1.5)2

=2.25

Area scale factor is 2.25

5 0
2 years ago
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